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Chapter 4 Q's - 7 011001110 0011100011 0001101110...

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Paul Robison CSC 160 Level 2, chap. 4 questions; 3, 4, 5, 7, 8, and 15 3. a) 11000= 24 b) 11001= 25 c) 1111111= 127 d) 1000000000= 1024 4. a) 23=00010111 b) 55=00110411 c) 275=too big using 8 bit. 11111111= 255 5. a) - 49 b) +794 c) – 1 d) -0
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Unformatted text preview: 7. 011001110 0011100011 + 0001101110 0100010001 8. a) +7.5=01111 x 2^3 b) -20.25= 11010001 x 2^5 c) -1/64= 000001 x 2^0 15. a) (false) OR (true) b) (true) AND (true) c) NOT (true) d) NOT [(false) OR (true)]...
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