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Unformatted text preview: n = 1 . 500 and the radius of the lens is R = 0 . 500 mm . For this case, calculate the focal distance f in millimeters for the values of h given below. Express your answers accurately to the nearest 0 . 0001 mm . Put your nal answers in the spaces provided. h ( mm ) f ( mm ) 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 Fiber Optic Ball Lens Five equations and fve unknowns sin 11 = n sin 21 Snells law at frst surace sin 11 = h/R ( h, R ) triangle 21 = 12 ( R, R ) equilateral triangle n sin 12 = sin 22 Snells law at second surace 22 = 11 sin (  11 ) R + f = sin 2( 11 21 ) R ( R, R + f ) triangle , law o sines Solving R + f R = sin (  11 ) sin 2( 11 21 ) f = R sin 11 sin 2( 11 21 )1 f = R h/R sin 2[ sin1 ( h/R )sin1 ( h/nR )]1 For n = 1 . 5 and R = 0 . 500 mm h ( mm ) f ( mm ) 0.05 0.2479 0.10 0.2416 0.15 0.2310 0.20 0.2158 0.25 0.1958 0.30 0.1704 0.35 0.1389 0.40 0.1001 0.45 0.0522...
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This note was uploaded on 04/29/2008 for the course ECE 4500 taught by Professor Gaylord during the Spring '08 term at Georgia Institute of Technology.
 Spring '08
 Gaylord

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