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4500PP06 - Power Received by Detector Differential area on...

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Power Received by Detector Differential area on surface of sphere d A = ( r dθ )( r sin θ dφ ) Differential solid angle d Ω = d A r 2 = sin θ dθ dφ Total power emitted by LED P t = π/ 2 θ =0 2 π φ =0 I Ro cos θ sin θ d θ d φ = I Ro sin 2 θ 2 π/ 2 0 φ 2 π 0 = π I Ro Cone of light received by the detector has a half apex angle of θ = θ t where sin θ t = a r Power received by the detector is
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