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4500PT04

# 4500PT04 - Thick Lens Imaging An object is placed to the...

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Unformatted text preview: Thick Lens Imaging ' An object is placed to the left of the lens shown-in the diagram below. All di- mensions given are in mm. It is desired to form a real image 'of the object such that the image is a speciﬁed size relative to the object (measured transverse to the axis of the op- ‘ tical system).'.The relative sizes are given below. ‘ V For each case, calculate, showing all work, the distance of the object from the left-most glass surface. For each case, calculate, showing all work, the distance of the im‘ age from the right-most glass surface. Express your answers in mm accurately to within \$0.1 mm. Put your answers in the spaces provided. For a 25% size image Distance of object from left—most glass = D ‘ mm Distanceof image from rightémost glass -_—- i . ' mm For a 50% size image " Distance of object from left—most glass 2 mm Distance of image from‘right—most glass 2 mm. For a 100% size image I Distance of object from left—most glass 2 I g ' " ' ‘ mm Distance of image from right—most glass 2 , . mm For the case of 100% size itnage, prepare,‘ on a separate sheet of paper, an accu- rate, scale drawing of the ray trace diagram. On your drawing, show the object, the par- allel ray, the focal ray, and the image. Also, on your drawing, show the F’- fecal point; the F foeal point, the H’ principal plane, and the H principal plane. ' Thick Lens Imaging Focal length, f = 51.6mm Real image, m < 0 Linear magniﬁcation, m = —0.25 = —1/4 Object distance 1 ,, s = (1 — ;)f = 5f = 5(51.6mm) = 258.0mm Distance of object from left-most glass = 258.0 — (51.6 — 23.7) = 230.1 mm Image distance 3’ = —ms = —(—1/4)258.0mm = 64.5mm Distance of image from right—most glass = 64.5 — (51.6 — 38.1) = 51.0 mm Linear magniﬁcation, m = ——O.50 = —1/2 Object distance 3 = (1 —~ 2 3f ,2 3(51.6mm) = 154.8mm Distance of object from left-most glass = 154.8 — (51.6 — 23.7) = 126.9 mm Image distance 3’ ——ms = —-(—1/2)154.8mm 77.4 mm - Distance of image from right-most glass 2 77.4 — (51.6 — 38.1) = 63.9 mm Linear magniﬁcation, m = —1.00 Object distance 3 = (1 — %)f = 2f = 2(51.6mm) = 103.2mm Distance of object from left-most glass = 103.2 — (51.6 — 23.7) = 75.3 mm Image distance s’ = —m3 = -(—1)103.2mm = 103.2mm Distance of image from right-most glass = 103.2 — (51.6 — 38.1) = 89.7mm ...
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