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Unformatted text preview: Fraunhofer Diffraction by FiveSlit Uneven Transmittance A spatial light modulator is adjusted such that the amplitude transmittance, f 5 u , is as shown in the figure. At the center ( x = 0), the amplitude transmittance is 100% ( t = 1). The transmittance then drops to 0% ( t = 0) at x = ± a/ 2. The transmittance is again 100% ( t = 1) at x = ± 7 a/ 4. The transmittance then again drops to 0% ( t = 0 . 00) at x = ± 9 a/ 4. The transmittance is once again 100% ( t = 1) at x = ± 31 a/ 8 and drops finally to 0% ( t = 0) at x = ± 33 a/ 8. The spatial light modulator is illuminated in air at normal incidence by a plane wave of freespace wavelength λ . Derive, showing all work, the amplitude of the farfield (Fraunhofer) diffraction pattern resulting from the diffraction of the plane wave by this amplitude transmittance function, f 5 u . Express your answer as A ( k x ) where A ( k x ) is a function of a and k x only , where k x is the xcomponent of the diffracted wavevector. Derive, showing all work,component of the diffracted wavevector....
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This note was uploaded on 04/29/2008 for the course ECE 4500 taught by Professor Gaylord during the Spring '08 term at Georgia Tech.
 Spring '08
 Gaylord

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