waterhw3 - alum is 22.5 g/m 3 . However, if a linear...

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13.13 10 6 0 10 12 0 15 5 0 15 6 0 20 3 0 20 4 0 25 4 0.01 25 2 0 30 7 0.01 30 5 0 35 10 0.01 35 9 0 10 10 0 10 5 0 15 4 0 15 3 0 20 3 0 20 3 0 25 3 0 25 5 0 30 5 0.01 30 7 0.01 35 7 0.01 35 9 0.01 Determine the least-cost method of coagulation such that a treated water turbidity of 3 NTU can be obtained. FeCl 3 , g/m 3 Turbidity, NTU Cost, $/m 3 Alum, g/m 3 Turbidity, NTU Cost, $/m 3 Alum + 1 g/m 3 Polyelectrolyte, g/m 3 Turbidity, NTU Cost, $/m 3 FeCl 3 + 1 g/m 3 Polyelectrolyte, g/m 3 Turbidity, NTU Cost, $/m 3 10 15 20 25 30 35 0 2 4 6 8 10 12 14 Jar Test Results Column G Column B Column B Column G Dosage, g/m3 Turbidity, NTU
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Chemical Cost, $/kg Alum 0.14 FeCl3 0.20 Polyelectrolyte 1.28 ((.0028-.0035)/2)+0.0035 Calculation of dose: As the plot above shows, the most cost effective coagulant mix to attain a turbidity of 3 NTU is alum (assuming linear relationship between data points). The most effective dosage of
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Unformatted text preview: alum is 22.5 g/m 3 . However, if a linear relationship is not assumed and only the scope of the data is defined, then 15 g/m3 FeCl3 + 1 g/m3 polyelectrolyte is the most cost effective coagulant mix to attain a turbidity of 3 NTU. Interpolation of $/m 3 : Interpolation between alum turbidity 2 and 3 NTU yields: cost = 0.00315 $/m 3 . From cost, dose = 22.5 g/m 3. (0.00315 $/m 3 ) / (0.00014 $/g) 1 2 3 4 5 6 7 8 9 10 11 12 13 0.01 0.01 0.01 0.01 Cost Analysis Column H Column C Column C Column H Turbidity, NTU Cost, $/m3...
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waterhw3 - alum is 22.5 g/m 3 . However, if a linear...

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