4500HWI04 - Interference Filter 1 A...

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Unformatted text preview: Interference Filter - 1 A “one-half-wavelength” thick interference filter is specified to pass 500 nm wave— length light at normal incidence. By rotating the angle of incidence of this filter it is de- sired to pass either only 488.0 nm blue light from an argon ion laser or only 514.5 nm ' green light from an argon laser as shown in the figure. The “one-half—wavelength” thick layers have a refractive index of 1.400. The surrounding regions have a refractive index of 1.500. Calculate, showing all work, the thickness of the “one—half—wavelength” thick re— gion. Specify which argon laser wavelength (488.0nm or 514.5 nm) can be passed by rotating the filter. Calculate, showing all work, the required angular rotation 04 in de— grees as measured in air that is required. Express all of your answers accurately to five significant figures. Put your answers in the space provided. Thickness of “one-half-wavelength” center region 2 nm The wavelength that can be passed is 488.0 nm 514.5nm. Circle one. Angle of incidence to pass above wavelength (1 = Interference Filter The 500nm wavelength filter can be tuned to the shorter wavelength of 488.0 nm. The tuning characteristic is 2 n d cos ,6 = m /\ For one half wavelength filters at normal incidence 2nd = A and so 2nd 2 500nm and so with n = 1.4 then d = 178.57 nm For tuning to 488.0 nm 488.0 nm cosfi 500nm and so ,8 578 Parallel glass plates do not affect the ray direction in air. Thus from Snell’s law 1.03ina = 1.4sin,8 and so a 17.7509°. ...
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This note was uploaded on 04/29/2008 for the course ECE 4500 taught by Professor Gaylord during the Spring '08 term at Georgia Tech.

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4500HWI04 - Interference Filter 1 A...

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