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Unformatted text preview: Reﬂection and Refraction at a Boundary  1 Light of freespace wavelength 546.1 nm (e line) is incident in air upon a planar
surface of BK7 glass. The angle of incidence is 60° measured counterclockwise from the normal. Both TE and TM polarizations are present in the incident light wave. For the transmitted and reﬂected waves7 calculate, showing all work, the quanti—
ties on the attached sheet. Express angles in degrees accurately to within 0.0001°. Ex— press fractions accurately to within 0.00001. Write your ﬁnal answers in the spaces pro— vided. TE Polarized Transmitted Wave Angle of transmitted wavevector
(with respect to normal to boundary) = Fraction of amplitude transmitted 2 Phase shift upon transmission 2 H Fraction of power transmitted TE Polarized Reﬂected Wave Angle of reﬂected wavevector
(with respect to normal to boundary) 2 Fraction of amplitude reﬂected = Phase shift upon reﬂection 2 Fraction of power reﬂected TM Polarized Transmitted Wave Angle of transmitted wavevector
(with respect to normal to boundary) = Fraction of amplitude transmitted = Phase shift upon transmission 2 Fraction of power transmitted TM Polarized Reﬂected Wave Angle of reﬂected wavevector
(with respect to normal to boundary) = Fraction of amplitude reﬂected = Phase shift upon reﬂection = Fraction of power reﬂected Reﬂection and Refraction at a Boundary  1 A = 546.1 nm 71 = 1.51825 01 = 60° 02 = sin_1[(n1/n2)sin01] = 34.77884°
03 = tan—1(n2/n1) = 56.62898° From Fresnel’s equations TE Polarized Transmitted Wave Angle of transmitted wavevector
(with respect to normal to boundary) 2 34.77884° Fraction of amplitude transmitted = 0.57240
Phase shift upon transmission 2 0° Fraction of power transmitted = 0.81716 TE Polarized Reﬂected Wave Angle of reﬂected wavevector
(with respect to normal to boundary) 2 60.0000° Fraction of amplitude reﬂected = —O.42760
Phase shift upon reﬂection : 180.0000° Fraction of power reﬂected = 0.18284 TM Polarized Transmitted Wave Angle of transmitted wavevector
(with respect to normal to boundary) = 34.77884° Fraction of amplitude transmitted = 0.63272
Phase shift upon transmission = 0° Fraction of power transmitted = 0.99845 TM Polarized Reﬂected Wave Angle of reﬂected wavevector
(with respect to normal to boundary) = 60.0000° Fraction of amplitude reﬂected = ——0.03938
Phase shift upon reﬂection = 180.0000° Fraction of power reﬂected = 0.00155 ...
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 Spring '08
 Gaylord
 Light, Polarization, Wavelength

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