4500PR04 - Reflection and Refraction at a Boundary - 1...

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Unformatted text preview: Reflection and Refraction at a Boundary - 1 Light of freespace wavelength 546.1 nm (e line) is incident in air upon a planar surface of BK-7 glass. The angle of incidence is 60° measured counter-clockwise from the normal. Both TE and TM polarizations are present in the incident light wave. For the transmitted and reflected waves7 calculate, showing all work, the quanti— ties on the attached sheet. Express angles in degrees accurately to within 0.0001°. Ex— press fractions accurately to within 0.00001. Write your final answers in the spaces pro— vided. TE Polarized Transmitted Wave Angle of transmitted wavevector (with respect to normal to boundary) = Fraction of amplitude transmitted 2 Phase shift upon transmission 2 H Fraction of power transmitted TE Polarized Reflected Wave Angle of reflected wavevector (with respect to normal to boundary) 2 Fraction of amplitude reflected = Phase shift upon reflection 2 Fraction of power reflected TM Polarized Transmitted Wave Angle of transmitted wavevector (with respect to normal to boundary) = Fraction of amplitude transmitted = Phase shift upon transmission 2 Fraction of power transmitted TM Polarized Reflected Wave Angle of reflected wavevector (with respect to normal to boundary) = Fraction of amplitude reflected = Phase shift upon reflection = Fraction of power reflected Reflection and Refraction at a Boundary - 1 A = 546.1 nm 71 = 1.51825 01 = 60° 02 = sin_1[(n1/n2)sin01] = 34.77884° 03 = tan—1(n2/n1) = 56.62898° From Fresnel’s equations TE Polarized Transmitted Wave Angle of transmitted wavevector (with respect to normal to boundary) 2 34.77884° Fraction of amplitude transmitted = 0.57240 Phase shift upon transmission 2 0° Fraction of power transmitted = 0.81716 TE Polarized Reflected Wave Angle of reflected wavevector (with respect to normal to boundary) 2 60.0000° Fraction of amplitude reflected = —O.42760 Phase shift upon reflection : 180.0000° Fraction of power reflected = 0.18284 TM Polarized Transmitted Wave Angle of transmitted wavevector (with respect to normal to boundary) = 34.77884° Fraction of amplitude transmitted = 0.63272 Phase shift upon transmission = 0° Fraction of power transmitted = 0.99845 TM Polarized Reflected Wave Angle of reflected wavevector (with respect to normal to boundary) = 60.0000° Fraction of amplitude reflected = ——0.03938 Phase shift upon reflection = 180.0000° Fraction of power reflected = 0.00155 ...
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This note was uploaded on 04/29/2008 for the course ECE 4500 taught by Professor Gaylord during the Spring '08 term at Georgia Institute of Technology.

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4500PR04 - Reflection and Refraction at a Boundary - 1...

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