HW_4Sol - ME3720B Homework#4 Solution Problems 5.12 5.22...

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1 ME3720B: Homework #4 Solution Problems 5.12, 5.22, 5.33, 5.58, 5.63
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3 See next page for the solution with SI units
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4 Problem 5.33 (SI units) Given condition: 2 1 14.71 lbf/in 101.4 kPa p == 2 2 501 lbf/in 3454.2 kPa p 1 70 F 294.26 K T = 2 190 F 360.93 K T = °= 33 1 ( ) 40 f /s 1.133 m /s AV t G / 20.5 Btu/lb 47.68 kJ/kg out Qm ± ± Mass balance: 12 mm m ±± ± Energy balance: 0( ) out c QW m h h =− + + ± ± ± Note that I already considered the direction of heat transfer as well as work with
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This note was uploaded on 04/28/2008 for the course ME 3720 taught by Professor Lee during the Spring '08 term at Georgia Tech.

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HW_4Sol - ME3720B Homework#4 Solution Problems 5.12 5.22...

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