CHEM 108-10 Test 3 Solutions

CHEM 108-10 Test 3 Solutions - 1 1 1 1 1 1 356 62 08206...

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CHEM108-10 Test #3 1/9 _____________________________ Name ___________________@tulane.edu Tulane e-mail C HEM 108-10 T EST #3 A PRIL 16, 2008 Time allotment: 50 min S OLUTIONS FROM T ESTS H ANDED IN BY STUDENTS ____________ 100 total points General Remarks Clearly show your work and identify each single step, how ever trivial it might look. To ensure partial credit, it is highly beneficial to support long conversion pathways of four or more conversion steps by a general conversion path outline (e.g. moles mass density). Unaccounted for data presented out of context will not be considered for partial credit. Results must be reported by using the correct number of significant figures. Illegible answers will not be considered for credit.
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CHEM108-10 Test #3 2/9 S UPPORTING I NFORMATION Acid-Base Chemistry: ] [ ] [ log HA A pK pH a + = b a W K K K × = 14 10 00 1 + × = = . ] [ ] [ OH H K W % 100 × = + HA of molarity initial HA from derived H of molarity ionization percent Thermodynamics: Values for R:
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Unformatted text preview: 1 1 1 1 1 1 356 62 08206 3145 8 = = = K mol Torr L K mol atm L K mol J R . . . Temperature Conversion: 0 C = 273 K Quadratic Equation: Solutions for a ac b b x c bx ax 2 4 2 2 = = + + : T q S rev = ) ( ) ( = reactants S v products S v S r p o o o S T H G = = ) ( ) ( reactants G products G G f r f P o o o = 2 1 1 2 1 1 T T R H K K o ln eq K RT G ln = o = ) ( ) ( reactants H products H H f r f P o o o CHEM108-10 Test #3 3/9 T HERMODYNAMIC P ROPERTIES T = 298K G f /kJ mol-1 K-1 H f /kJ mol-1 S/J mol-1 K-1 O 2 (g) 0 0 205.1 N 2 (g) 0 0 191.6 NO(g) 86.55 90.25 210.8 NO 2 (g) 51.31 33.18 240.1 N 2 O(g) 104.2 82.05 219.9 N 2 O 4 (g) 97.89 9.16 304.3 P REFIXES...
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CHEM 108-10 Test 3 Solutions - 1 1 1 1 1 1 356 62 08206...

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