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Unformatted text preview: 2 .5 2 1 2 5 1 2 X s G s s s s = = = + + + + . From Laplace Transform Table: note the transform pair sin at e t ωand ( ) 2 2 s a + + . Using the equivalences 1 a = and 2 = , gives: ( ) ( ) .5 sin 2 t x t g t e t= = METHOD 2: From Problem 3, ( ) ( ) ( ) .2 .2cos2 .1sin 2 t x t h t e t t= =+ . Using the derivative approach ( ) ( ) ( ) ( ) ( ) .2 .2cos2 .1sin 2 .2cos2 .1sin 2 .4sin 2 .2cos2 t t t d e t t dh t x t e t t e t t dt dt + = = = ++ Reducing the final expression gives ( ) .5 sin 2 t x t e t=...
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This note was uploaded on 02/29/2008 for the course ME 242 taught by Professor Perreira during the Spring '08 term at Lehigh University .
 Spring '08
 Perreira
 Laplace

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