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Chapter 08a - Chapter 8A Linear and Rotational Motion x...

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Chapter 8A 1 Linear and Rotational Motion displacement velocity acceleration equations of motion v a v = v 0 + at x = 1 2 v 0 + v ( 29 t x = v 0 t + 1 2 at 2 x = vt - 1 2 at 2 v 2 = v 0 2 + 2 a x x θ ϖ α ϖ = ϖ 0 + α t θ = ϖ 0 t + 1 2 α t 2 θ = ϖ t - 1 2 α t 2 ϖ 2 = ϖ 0 2 + 2 α θ θ = 1 2 ϖ 0 + ϖ ( 29 t
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Chapter 8A 2 Torque τ = torque F = magnitude of force vector r = magnitude of position vector (lever arm) Units: Newton · meter Counterclockwise is (+) τ = F · r F r 9 0 °
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Chapter 8A 3 Torque Only the force component that is perpendicular to the lever arm contributes to the torque: τ = F sin θ ( 29 r F r θ
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Chapter 8A 4 Equilibrium An object is in equilibrium if there is no net force and no net torque acting on it. Σ r F = 0 Σ F x = 0 Σ F y = 0 Σ τ = 0 There is no linear acceleration and no angular acceleration.
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Chapter 8A 5 Equilibrium This new definition of equilibrium allows us to solve problems that can’t be solved using forces alone.
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Chapter 8A 6 Typical Equilibrium Problem Two weights are balanced on a see-saw.
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