Exam 3 Fall 2005
Chapters 13 – 18
Name ____________________________________
MULTIPLE CHOICE. Choose the one alternative that
BEST
completes the statement or answers the question.
Chapter 13
1. If a pea that is homozygous recessive for height (tt) and seed color (ss) is crossed with a pea that is homozygous dominant for height (TT) and seed color (SS) the
offspring will be heterozygous (TSts). If the offspring are allowed to self-fertilize what will the phenotypic ratio of the offspring be?
A. 1:2:1
B. 3: 1
C. 1: 1
D. 1: 2: 2: 1
E. 9: 3: 3: 1
2. How many unique gametes could be produced through independent assortment by an individual with the genotype AaBbCCDdEE?
3. A man who carries an X-linked allele (gene) will pass it on to
4. Regarding an allelic pair for flower color in snapdragons, heterozygotes have pink flowers, whereas the two homozygotes have red flowers or white flowers. When
plants with red flowers are crossed with plants with white flowers, what proportion of the offspring is expected to have pink flowers?
5. Whenever either or both gene A or gene B is present, red color is produced. A cross of AaBb
×
AaBb can be expected to yield how many red offspring out of 16?
Assume the genes are not linked.
A.
1
B.
4
C.
12
D.
15
E.
16
6. Pepper color is a trait that exhibits epistasis. If a pepper plant that has red peppers is heterozygous for pepper color (Rr), which of the following represents the
phenotypic ratio of the offspring?
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7. Which of the following is due to the principle of segregation?
8. Freckles are a dominant trait in humans. To determine the genotype of a man with freckles (F?), the best person to mate him with would be
A.
His mother
B.
His sister
C.
Any woman with freckles.
D.
Any woman with no freckles.
E.
Unable to determine from the information given
Chapter 14

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- Fall '07
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- DNA, a. b. c., b. c. d., A. B. C. D.
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