Soln to Cpt 10 Problems

Soln to Cpt 10 Problems - CHAPTER 10 10.1 (a) (b) (c) (a)...

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CHAPTER 10 10.1 (a) df A = c – 1 = 5 – 1 = 4 (b) df W = n – c = 35 – 5 = 30 (c) df T = n – 1 = 35 – 1 = 34 10.2 (a) SSW = SST – SSA = 210 – 60 = 150 (b) MSA = SSA c –1 = 60 5 – 1 = 15 (c) MSW = SSW n c = 150 35 – 5 = 5 (d) F = MSA MSW = 15 5 = 3 Example 10.5 Source df SS MS F Among groups 4 – 1 =3 80 x (3) = 240 80 80 ÷ 20 = 4 Within groups 32 – 4 = 28 560 560 ÷ 28 = 20 Total 32 – 1 = 31 240 + 560 = 800 Example 10.10 (a) H 0 : μ A = B = C = D H 1 : At least one mean is different. ANOVA Source of Variation SS df MS F P-value F crit Between Groups 1986.475 3 662.1583 48.10838 1.12E-12 2.866265 Within Groups 495.5 36 13.76389 Total 2481.975 39 Since the p -value is essentially zero, we can reject H 0 . There is sufficient evidence of a difference in the average strength of the four brands of trash bags. (b) Tukey Kramer Multiple Comparisons Sample Sample Absolute Std. Error Critical Group Mean Size Comparison Difference of Difference Range Results 1 35.4 10 Group 1 to Group 2 0.9 1.17319601 4.446 Means are not different 2 36.3 10 Group 1 to Group 3 0.5 1.17319601 4.446 Means are not different 3 34.9 10 Group 1 to
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Soln to Cpt 10 Problems - CHAPTER 10 10.1 (a) (b) (c) (a)...

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