hmwrk 2 - 958 1 2 1023 c D i = 102.3mm =.1023m V = 2.1m/s =...

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1. -1.5 -1 -0.5 0 0.5 1 1.5 sin(x) 1/2sin(2x) 2. 1 5 9 13 17 21 25 29 -1 -0.5 0 0.5 1 wireframe 0.5-1 0-0.5 -0.5-0 -1--0.5 3. F=ma The tension in each cord is the mass of the cord times the acceleration due to gravity. F = N kg N kg 981 1 81 . 9 * 100 =
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4. Plug values into the equation and solve. The important step is to convert the diameter of the pipe, given in mm, to m. a. D i = 102.3mm = .1023m V = 2.1m/s _ = 998 kg/m 3 _ = 9.82 * 10 -4 Pa.s Nre = turbulent s Pa m kg s m m = = 5 4 3 10 * 18 . 2 . 10 * 82 . 9 / 998 * / 1 . 2 * 1023 . b. D i = 102.3mm = .1023m V = 2.1m/s _ = 958 kg/m 3 _ = 3.1 * 10 -4 Pa.s Nre = turbulent s Pa m kg s m m = = 5 4 3 10 * 64 . 6 . 10 * 1 . 3
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Unformatted text preview: / 958 * / 1 . 2 * 1023 . c. D i = 102.3mm = .1023m V = 2.1m/s _ = 1400 kg/m 3 _ = 10 Pa.s Nre = ar la s Pa m kg s m m min 1 . 30 . 10 / 1400 * / 1 . 2 * 1023 . 3 = = d. D i = .61m V = 6.3m/s _ = .95 kg/m 3 _ = 2.1 * 10-5 Pa.s Nre = turbulent s Pa m kg s m m = = − 5 5 3 10 * 74 . 1 . 10 * 1 . 2 / 95 . * / 3 . 6 * 61 . 5. Linearize r = kx a +y b ln(r ) = ln(kx a ) + ln(y b ) ln(r ) = ln(k) + ln(x a ) + ln(y b ) ln(r ) = ln(k) + aln(x) + bln(y)...
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hmwrk 2 - 958 1 2 1023 c D i = 102.3mm =.1023m V = 2.1m/s =...

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