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Unformatted text preview: = 2 r3 s + t r 4 s2 t s 5 t t , where x 2 = r , x 4 = s , and x 6 = t . Setting r = 1 and s = t = 0, we obtain a solution v 1 = 2 1 . Similarly, v 2 = 3 4 1 corresponds to s = 1, r = t = 0, and v 3 = 12 5 1 corresponds to r = s = 0 and t = 1. It follows that the set of solutions to A x = is Span { v 1 , v 2 , v 3 } ....
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 Spring '03
 BUSS
 Vectors, Gaussian Elimination, Row echelon form, 3 span, 1 Sec

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