122_t3_soln

122_t3_soln - Mutiple Choice: select the best answer; no...

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Unformatted text preview: Mutiple Choice: select the best answer; no partial credit. 1. If the torque on a rigid body is 6.00Nm and the moment arm is 2.00m, what is the magnitude of the force causing the rotation? ' a.) 1.0N 7;: Fa : (300 NM b. 6.0N 3.0N F : 6,00Uw _ b.00NM d.) 2.0N /“‘ ' 2 e.) 10.0N d 00‘“ \ k:3ooM 2. The moment of inertia of a circular disk of radius R and mass M about an axis of rotation through the center of the disk is I = V2 MR2. What is the moment of inertial about an axis of rdtation on the edge of disk, parallel to the axis of rotation - through the Center? (hint: use the parallel axis theorem). D: R 1044: ‘EMR Ia ~g—MR2.+ MRZ ligzMR’Z 3. A rigid body rotates with constant angular acceleration a=10.0 rad/s2. If the body starts at rest, what time does it take to reach an angular speed of (0:200 rad/s? ' w‘c : wc- +o<JC c)3.00S 22:33: w: o W = oLJC % fl, t: 0L — [00 vctcL’sZ Problem 4 Two masses hang from a frictionless, massless pulley. Assume the strings have negligible mass. The values of the masses are m1=2.00kg and m2=3.00kg. C '7 m J A T T a.) Draw the free body diagram of each mass. «4; A J i . F3 ‘3 b.) Find the value of the acceleration of the system a and the tension of the string T. Use g=10.0 m/sz. (hint: use Newton’s Second Law). ZFY : ¢ A q \—\M\C} ~ “4ch #Z\ TAM} a v4ch (ml—mm : (MIHMQK «= Mm : amt/n) M (4+ Wilt“, 3 3.00ltj ’r‘2.oo\:j ‘ S . Z , <2oow><www> Problem 4 (continued) c) Starting from rest, the masses move a distance Ay in t=0.10()s. Find the work done by the tension T of the string on mass #1. (hint: you must find Ay which is the displacement in the y-direction). ge‘r A7.- y4 = y]. + vii + chLJCL Vtwo Q7 ‘ #73 = éatz $3: Jz‘dczj‘ m: ’ if A}: fizwwfi W= (flout). (Jia 1% d Problem 5 Ball #1 initially moVing at speed v,- in the positive x direction undergoes a glancing collision with ball #2, initially at rest. The balls leave at the same angle relative to the x- / axis but at different speeds v1f=10.Om/s and V2F5.00m/S. @ V = ‘O-Oyl . / \F 5 4.00m, x” G Vc I ’ ; _._..._-.....;;_’ ,-.?;_.,_. \ ©l I M BEF ORE AFTER . \ V :5,00MA) 2 S a.) If m2=1.00kg, use conservation of linear momentum in the y direction to find ml, the mass of ball #1. P = P ’t 7% 7.: MV ‘l' MV 0 | ‘7f 2 t ' : - (‘01 V‘ -: V\ Slqa V17 V243). 9 7% 1° t V ‘ a mi/ 5‘ 9 :N " “A O \ \fSu/t 11C . ‘ 1M M‘V‘ 1F V21; 1 WM: V21: M2 -_: S'OOMi‘ (Loom VH; 10.0 “4' S Problem 5 (continued) b.) Using your result from part a) and conservation of linear momentum in the x- direction, what is the value of vi, the initial velocity of mass #1? F 7 ,2. V7— IM|VL l/‘/‘\\:.)(_E + W11 )9? \F ? V‘M/ 1: \M\V\ Lesa + Mlvzi’cosg \ L P C0 ‘9 VC 3 3—6 W‘VI-F + WZVZ'P) WI (059 = id. ~ 35‘ ‘3? New ‘+ '-Ma><$'”°“/sfl Problem 6 A ball is dropped with mass of 1.00kg with initial downward velocity vi=10.0m/s from a height 13.0m from the ground. The ball lands on a platform attached to a spring. The spring’s original length is 3.00m. The ball compresses the spring and comes to rest 1.00m from the ground. What is the spring constant k of the spring? Use g=lO.0rn/s2 and assume that the gravitational potential energy of the ball is zero at ground level. Neglect the mass of the platform on the spring. ...
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This note was uploaded on 04/29/2008 for the course PHYS 122 taught by Professor Pope during the Spring '08 term at Clemson.

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122_t3_soln - Mutiple Choice: select the best answer; no...

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