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Unformatted text preview: 3.7 The solid spindleAB has a diameter d, = 1.5 in. and is made ofa steel with an '
allowable shaming stress of12 ksi, while sleeve CD is made ofabrass with an allowable
shearing stress of 7 ksi. Determine the largest torque T that can be applied at A. Problem 3.7 SJI‘J sFMaUe AB ‘ c = Ji&¢ = 57:04:?) = 0.75 in.
J 2 Ed = §(o.7s)‘ = 0.14am! M 21min: 75:9“
J'z’ (0.4470001) H  . ‘
Tm = c J: Wis‘ﬂ— — 7.953? «mmm
Sﬂeau‘e. CD 3 Ca: $501 = 13(39‘) = l—5 Eh.
C. = C‘;L —t = r5_o.25 = !25 m. J: 'iLCJ cl”) 2 l{(l.5“L2s“}= 4.:172 m" ~ It: ($11300) __ ' . .
l%‘: “—01“— :"———’:§——— — lq,'213 klpIV‘ Alwwa/Q‘pe Vat/“J2 6‘? +0Vﬁue, T is +Le smdﬂeﬁ. T: 7.?5' LhYx{n 4 Problem 3_ 1 3 3.13 Under normal operating conditions, the electu'c motor exerts a torque of 2.8 kN
 m on shaft AB. Knowing that each shaﬁ is solid, determine the maximm sheeting
stress in (a) shaft AB, (1:) shaft BC, (0) shaft CD. T1; = L4 ICN  m
T12: = 0.9 L'N  m " 48 mm To = 0.5 kN  m 46 mm (0.] SLA'H‘ AB: TAB“: 2,8 kH‘Mn : 23x10? NMJ C=Ji91= 23mm= 0.028m ,1 To 21‘ “ (2.}(2.8><IO$) : L = —  ._
M J" Fr.“ 17 (0.01213 2110:4069; 215311 Mmei (m 5qu 8C: Tear LL; Wm = LLJXIog Nth agar: 2%“ 0.024% 7: _ 31 q mason?)
k" we“ " w(ooz=n3 (cl 3315+ CD: 725:05kumn : 0.5xlozN.m) C='§a’r Z'f'mm: 0.02‘fm ,‘5, _ QT __ (23(0.5’xl03)_
176* ' “(0.02433 ‘ G4‘+7>«lO‘Pa fat: Q‘lﬁ'HPot 4" 93.053 xnf Pa 11:. = 2%. 0 Met ‘4 'LLD " . r 3.72 The design of a machine element calls for a 40 mm—outerldiameter strait to
: PrOblem 3‘ 72 transmit 45 kW. (0) Ifthe speed of rotation is 720 rpm, determme the maxrmum
' shearing stress in shaﬁ: a, (b)1fthe shaﬁ of rotation can tae Increased 50% to 1980
rpm, determine the largest inner diameter of shaﬁ b for Whlch the rnaxrmum sheanng stresswillbethe sameineaeh shaft.
m F= 7:29 = :2 Hz P= 95%}: Hex/o" w
13 ass/03 r.
= w———~— 6.8 ‘ C‘: at”! = 20 mm": CLOZOMe 1’: I? r 37% : ———(27rx(gf’jg:?§ = LEILF/H’V/Oc Pa. 2;”: 47.5MP0..4
(H ‘P’ [23:0 =18 Hz Trﬁé¥w T 397.3% um
T T T}; r #1255sz C'L}: C’j' 27:32
cf: 00201—W ‘3 $3.333}be
c, r razmzo’g m = {5.20 m Problem 3.35 3.35 The torques shownﬁ'e exerted on
shafts are solid and made of brass (G = 39
(am and B, (b) A and C. pulleys A, B, and C. Knowing that both
GPa), determine the angle of twist between 120033111 (a) [Maﬁa 0'? “(LWI‘S'IL between A emof B
The = Ltoo MMJ L“; L2 m
'c = 9+9! : 0.0L?“ 6 = 37:40" fa
er%rc" 79.52%” M“ _ TL  (HooML'z) , __ _ _.___,__________
(pm 5: (sﬁxroﬁcﬂsleo‘?)  0.154772 m! f) 90M; ‘— 337 a f) “
(b5 Amjﬂg a‘P dean's" Le‘llweem A a”! C T85: goo NM 3L“: 1.8m) c=iot €0.03: m, G = 3956/59: Jag gt} =E(o.0203"r 25:.327xto" m” ‘ : (SOOKLM __
59'3" m _ 0*‘*““2”t ’3 so”: = (pmfﬂu cpacﬁ o.15477290.Hmmzapovgtaomt? qﬂmc 0350"? 4 ...
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