Chapter_10_Problems

# Chapter_10_Problems - Problem 10-4 The angular position of...

This preview shows pages 1–3. Sign up to view the full content.

Problem 10-4 θ = 4.0t – 3.0t 2 + t 3 a) At t = 2.0 ω = 4.0 rad/s b) At t = 4.0s ω = 28 rad/s e) α = 18 rad/s 2 The angular position of a point on the rim of a rotating wheel is given by θ = 4.0 t – 3.0 t 2 + t 3 , where θ is in radians and t is in seconds. What are the angular velocities at (a) t = 2.0 s and (b) t = 4.0 s? (c) What is the average angular acceleration for the time interval that begins at t = 2.0 s and ends at t = 4.0 s? What are the instantaneous angular accelerations at (d) the beginning and (e) the end of this time interval? ω = dθ/dt =4.0 – 6.0t + 3.0t 2 α = dω/dt = -6.0 + 6.0t c) α av = ∆ω/∆t = (24 rad/s)/2.0 s α av = 12 rad/s 2 d) α = 6.0 rad/s 2 ω = 4.0 – 6.0(2.0) + 3.0(2.0) 2 ω = 4.0 – 6.0(4.0) + 3.0(4.0) 2 α = -6.0 + 6.0(2.0) At t = 2.0 At t = 4.0s α = -6.0 + 6.0(4.0)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
In the time it takes the light to travel 2L, the wheel turns through an angle of ∆θ = 2π/500 ∆θ = 1.26 x 10 -2 rad The time required to travel 2L is ∆t = 2L/c
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 4

Chapter_10_Problems - Problem 10-4 The angular position of...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online