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Unformatted text preview: 1 2 3 4 r v r v r v r v Current= B =0 B " B =0 zero CCW zero CW 4. A permanent magnet moves through a loop of wire as shown. Below is the flux to the right as a function of time. Sketch the induced current as a function of time Since flux to the right is decreasing, induced current will produce additional flux through the loop to the right. This is the direction of the current arrow in the figure, so current is positive. 5. The coil of five turns of wire has a total resistance of 1 . Calculate the maximum magnitude of the induced current for motion in 4. The maximum EMF is d " / dt # 0.002 T $ m 2 /0.2 s = 0.01 V for each turn of wire. The coil has five turns of wire. The total EMF is then 0.05V, and the maximum current is 0.05V/1 =0.05A=50mA. N S " TIME (sec) + 1 mT " m 2 " 1 mT # m 2 0.1 0.2 0.3 0.4 TIME (sec) 0.1 0.2 0.3 0.4 I I...
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This note was uploaded on 04/29/2008 for the course PHYS 208 taught by Professor Rzchowski during the Spring '08 term at Wisconsin.
- Spring '08