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Unformatted text preview: ] [HA] logK a = log[H + ]+ log [A ] [HA] logK a = log[H + ] log [A ] [HA] pK a = pH log [A ] [HA] pH = pK a + log [A ] [HA] Polyprotic acid A simplified way is to consider when one molecule of HA-dissociates to give an H + , another molecule of HA-can pick it up to give H 2 A: HA- H + + A 2-K eq = K a2 H + + HA- H 2 A K eq = 1/K a1 Net reaction: 2HA- H 2 A + A 2-K eq = K a2 /K a1 pH = pK a1 + pK a2 2...
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This note was uploaded on 02/21/2009 for the course BIS 102 taught by Professor Hilt during the Spring '08 term at UC Davis.
- Spring '08