Stat 13C - Answers to the Sample Final - F08

Stat 13C - Answers to the Sample Final - F08 - Stat 13C F J...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Stat 13C Answers to the Sample Final Fall 2008 F. J. Samaniego 1. Drawing a probability tree is helpful, though not mandatory. Let W 1 be the event that Penn State wins the Fiesta Bow and let W 2 be the event that Iowa wins the Rose Bowl. The tree you might have drawn has four paths. The two you want (using Ls for losses) are W 1 L 2 and L 1 W 2 . The probability of winning exactly one bet is (.4)(.3) + (.6)(.7) = .54. 2. The “box” method will help here. P(M c |C c ) = P(M c C c ) / P(C c ) = (.4) / (.6) = 2/3. 3. Definitely a tree problem. Let G 1 be the unloaded gun and G 2 the other. Let B be the event that a bullet comes out when the gun is fired. P(B) = (1/2)(0) + (1/2)(1/3) = 1/6. 4. A Bayes problem. P(G 1 |B c ) = P(G 1 B c ) / P(B c ) = 3/5. 5. X ~ B(6, 1/3). P(X = 4) = 4 6 (1/3) 4 (2/3) 2 = .0823. 6. Approximate p as .3. Then, approximately, X ~ B(10, .3). From Table 1, P(X ≥ 5) = 1 - .850 = .150. 7. Let X ~ B(72, 1/3);
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 02/21/2009 for the course STATS 013 taught by Professor Leong during the Fall '07 term at UC Davis.

Page1 / 2

Stat 13C - Answers to the Sample Final - F08 - Stat 13C F J...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online