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Unformatted text preview: The following conversion factors may be helpful in solving the pressure conversion problems: 1 atm = 101.3 kPa = 1.013 bar = 760 torr = 760 mm Hg = 14.7 psi Liquid chlorotribromomethane has a density of 2.71 g/mL. A barometer is constructed using chlorotribromomethane instead of mercury. If the atmospheric pressure 0.982 atm, the height of the chlorotribromomethane column in the barometer is mm. The density of liquid mercury is 13.6 g/mL. The pressure exerted by a column of a liquid can be expressed as the product of its density and the column height: P = D x h For two liquids, A and B, that exert the same pressure P = D A x h A = D B x h B Since the conversion factor between mm Hg and atmospheres is known, first express the pressure of 0.982 atmospheres in mm Hg: 0.982 atm x (760 mm Hg / atm) = 746 mm Hg Substituting A for chlorotribromomethane and B for mercury gives h A = (D Hg /D A ) x h Hg = (13.6 g/mL / 2.71 g/mL) x 746 mm = 3.75E+3 mm An automobile tire is inflated to a pressure of 28.1 psi. Express this pressure in atmospheres, kilopascals, bars, and millimeters Hg. Hint: 1 atm = 101.3 kPa = 1.013 bar = 760 torr = 760 mm Hg = 14.7 psi 1.91 atm 194 kPa 1.94 bar 1.45E+3 mm Hg Feedback: The following conversion factors may be used: 1 atm = 101.3 kPa = 1.013 bar = 760 mm Hg = 14.7 psi Convert 28.1 psi to atm: 28.1 psi x (1 atm / 14.7 psi) = 1.91 atm Convert 28.1 psi to kPa: 28.1 psi x (101.3 kPa / 14.7 psi) = 194 kPa Convert 28.1 psi to bar: 28.1 psi x (1.013 bar / 14.7 psi) = 1.94 bar Convert 28.1 psi to mm Hg: 28.1 psi x (760 mm Hg / 14.7 psi) = 1.45E+3 mm Hg A student reads a barometer in the laboratory and finds the prevailing atmospheric pressure to be 732 mm Hg. Express this pressure in atmospheres, kilopascals, torrs, and bars. Hint: 1 atm = 101.3 kPa = 1.013 bar = 760 torr = 760 mm Hg = 14.7 psi 0.963 atm 97.6 kPa 732 torr 0.976 bar Feedback: The following conversion factors may be used: 1 atm = 101.3 kPa = 1.013 bar = 760 torr = 760 mm Hg Convert 732 mm Hg to atm: 732 mm Hg x (1 atm / 760 mm Hg) = 0.963 atm Convert 732 mm Hg to kPa: 732 mm Hg x (101.3 kPa / 760 mm Hg) = 97.6 kPa Convert 732 mm Hg to torr: 732 mm Hg x (760 torr / 760 mm Hg) = 732 torr Convert 732 mm Hg to bar: 732 mm Hg x (1.013 bar / 760 mm Hg) = 0.976 In the winter, a heated home in the Northeast might be maintained at a temperature of 80 o F . What is this temperature on the Celcius and Kelvin scales?...
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This note was uploaded on 02/22/2009 for the course CHEM 102a taught by Professor Hanusa during the Fall '06 term at Vanderbilt.
 Fall '06
 Hanusa
 Chemistry

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