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1.1.IDENTIFY:
Convert units from mi to km and from km to ft.
SET UP:
, 1
, 12
1 in.
2.54 cm
=
km = 1000 m
in. 1 ft
=
, 1
.
mi = 5280 ft
EXECUTE:
(a)
23
5280 ft
12 in.
2.54 cm
1 m
1 km
1.00 mi
(1.00 mi)
1.61 km
1 mi
1 ft
1 in.
10 cm
10 m
⎛⎞
⎛
⎞
⎛
⎞
⎛
⎞
==
⎜⎟
⎜
⎟
⎜
⎟
⎜
⎟
⎝⎠
⎝
⎠
⎝
⎠
⎝
⎠
(b)
32
3
1 in.
1 ft
1.00 km
(1.00 km)
3.28 10 ft
1 km
1 m
2.54 cm
12 in.
⎛
⎞
⎛
⎞
⎜
⎟
⎜
⎟
⎝
⎠
⎝
⎠
×
E
VALUATE
:
A mile is a greater distance than a kilometer. There are 5280 ft in a mile
but only 3280 ft in a km.
1.5.IDENTIFY:
Convert volume units from
to L.
3
in.
SET UP:
. 1
3
1 L
1000 cm
=
in.
2.54 cm
=
.
EXECUTE:
( )
()
( )
3
33
327 in.
2.54 cm in.
1 L 1000 cm
5.36 L
××
=
E
VALUATE
:
The volume is
.
is less than
, so the volume in
is a
larger number than the volume in
.
3
5360 cm
3
1 cm
3
3
cm
3
in.
1.13.IDENTIFY:
The percent error is the error divided by the quantity.
SET UP:
The distance from Berlin to Paris is given to the nearest 10 km.
EXECUTE:
(a)
3
3
10 m
1
.
11
0%
.
890 10 m
−
=×
×
(b)
Since the distance was given as 890 km, the total distance should be 890,000 meters. We know the
total distance to only three significant figures.
E
VALUATE
:
In this case a very small percentage error has disastrous consequences.
1.24.IDENTIFY:
Estimate the number of beats per minute and the duration of a lifetime.
The volume of blood
pumped during this interval is then the volume per beat multiplied by the total beats.
SET UP:
An average middleaged (40 yearold) adult at rest has a heart rate of roughly 75 beats per
minute. To calculate the number of beats in a lifetime, use the current average lifespan of 80 years.
EXECUTE:
9
beats
60 min
24 h
365 days
80 yr
75 beats/min
3 10 beats/lifespan
1 h
1 day
yr
lifespan
N
⎛
⎞
⎛
⎞
⎛
⎞
⎜
⎟
⎜
⎟
⎝
⎠
⎝
⎠
×
9
3
7
blood
3
1 L
1 gal
3 10 beats
50 cm /beat
4 10 gal/lifespan
1000 cm
3.788 L
lifespan
V
×
⎛
⎞
⎜
⎟
⎝
⎠
×
E
VALUATE
:
This is a very large volume.
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This note was uploaded on 04/29/2008 for the course PH 1110 taught by Professor Kiel during the Fall '08 term at WPI.
 Fall '08
 Kiel

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