ex5 - Maximum Power Transfer Load Resistance Power...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Experiment 5 Datasheet Name:_________________ Section: _________ The Superposition Theorem Step 1 Contribution to Vo of: 9 V source 15 V source Both sources => total Step 2 Total Vo from above [1] Calculated Vo [2] Directly Measured Vo [3] % Error Between [1] and [2] % Difference Between [1] and [3] Compare [1] above with both [2] and [3] above. Comment on the error calculated above. Thevenin’s and Norton’s Theorems Steps 1 – 4 Quantity Measured Value Calculated Value % Error I 2.2 k ---- ---- V Th I sc R Th = V Th / I sc Step 5 I 2.2 k Does this value agree with the value obtained in Step 2? Explain.
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Maximum Power Transfer Load Resistance Power Absorbed < R Th < R Th < R Th ≈ R Th > R Th > R Th > R Th Make a plot of Power Absorbed v. Load resistance using the values obtained above. Does the plot peak at R Th ? Is the plot symmetrical about the peak value? Do you expect it to be? Explain. Wheatstone Bridge and Resistance Measurements Step 1 Measure three resistors. Resistance Measured by Bridge Resistance Measured by DMM % Difference R 1 R 2 R 3 Step 2 Nominal Resistance Resistance Measured by Bridge % Difference R 1 R 2 R 3 Comment on any variations of the results....
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern