8 - STAT 350 Fall 2008 Homework #8 Solution through Lecture...

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STAT 350 – Fall 2008 Homework #8 – Solution through Lecture #12 You can get p-values that are more precise than what is possible using the Chi-Squared Table in the Appendix of your textbook in Excel using the function “ChiDist”. For example, if your chi- square statistic is 30.54 and the degrees of freedom is 9, in Excel type “=ChiDist(30.54,9)” and excel will return the p-value. Text Exercises Chapter 8 problems #42, 44, 46 For each of the text problems, your work MUST show (i) the table of expected counts, (ii) the value of the Chi-Square statistic, (iii) the degrees of freedom for the test, and (iv) the p- value of the test. 8.42 Business Engineering Social ScienceAgriculture TOTAL 0.4 0.3 0.2 0.1 1 48 36 24 12 120 52 38 21 9 120 (O-E) 2 /E: 0.3333333330.111111111 0.375 0.75 1.569444 χ 2 = 1.569444, df = 4-1 = 3, p -value = 0.666 Therefore we would not reject the null hypothesis that the percentages for the 4 catageories are 40%, 30%, 20% and 10%, respectively. 8.44 location (i) π i expected frequencies observed counts expected counts (O-E) 2 /E 1 0.033333 4 6.666667 1.066667 2 0.066667 15 13.33333 0.208333 3 0.1 23 20 0.45 4 0.133333 25 26.66667 0.104167 5 0.166667 38 33.33333 0.653333 6 0.166667 31 33.33333 0.163333 7 0.133333 32 26.66667 1.066667 8 0.1 14 20 1.8 9 0.066667 10 13.33333 0.833333 10 0.033333 8 6.666667 0.266667 Sum 1 200 200 6.6125 χ 2 = 6.6125, df = 10-1 = 9, p -value = 0.6774. Therefore we would not reject the null hypothesis that the true (long-run) proportion of requests for location i is (5.5 - | i – 5.5|)/30 Homework #8 – Solution Page 1 of 5
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This note was uploaded on 02/23/2009 for the course STAT 350 taught by Professor Staff during the Fall '08 term at Purdue University.

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8 - STAT 350 Fall 2008 Homework #8 Solution through Lecture...

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