IHD - to the reference hydrocarbon • for each atom of a...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
CH 310 N 1 Revision on:1/29/2008 The index of hydrogen deficiency (IHD): the sum of the number of rings and pi bonds in a molecule To determine IHD, compare the number of hydrogens in an unknown compound with the number in a reference hydrocarbon of the same number of carbons and with no rings or pi bonds the molecular formula of the reference hydrocarbon is C n H 2n+2 (H reference - H molecule ) 2 IHD = for each atom of a Group 7 element (F, Cl, Br, I), add one H no correction is necessary for the addition of atoms of Group 6 elements (O,S)
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: to the reference hydrocarbon • for each atom of a Group 5 element (N, P), add one hydrogen Problem: isopentyl acetate has a molecular formula of C 7 H 14 O 2 . Calculate its IHD • reference hydrocarbon C 7 H 16 • IHD = (16-14)/2 = 1 Problem: calculate the IHD for niacin, molecular formula C 6 H 6 N 2 O • reference hydrocarbon C 6 H 16 • IHD = (16 - 6)/2 = 5 O O Isopentyl acetate N NH 2 O Niacin...
View Full Document

This note was uploaded on 02/23/2009 for the course CH 310n taught by Professor Iverson during the Spring '08 term at University of Texas.

Ask a homework question - tutors are online