chapter30---PHY 131 JAB

chapter30---PHY 131 JAB - 1 Chapter 30: Inductance 2 Coil 1...

Info iconThis preview shows pages 1–10. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 Chapter 30: Inductance 2 Coil 1 Coil 2 A variable current I 1 flows in coil 1. I 1 then induces a current in coil 2. 1 21 2 I N The flux ( 21 ) through coil 2 due to coil 1 is 30.1: Mutual inductance 3 Writing this as an equality 1 21 2 MI N = Where M is the mutual inductance. It depends only on constants and geometrical factors. The unit of inductance is the henry (1H = 1Vs/A). The induced emf in the coils will be dt dI M dt d N dt dI M dt d N 2 12 1 1 1 21 2 2- = - =- = - = 4 Self-inductance is for when a current carrying coil induces an emf in itself. LI N = The definition of self-inductance (L) is 30.2: Self-inductance and inductors 5 Example: The current in a 0.080 Henry solenoid increases from 20.0 mA to 160.0 mA in 7.0 s. Find the average emf in the solenoid during that time interval. ( ) V 10 6 . 1 s . 7 mA 20 mA 160 H 080 . 3- - = -- = - = - = t I L t N 6 Example: Consider a solenoid of length a that carries a current I . The solenoid has circular cross-section of area A . What is the self-inductance of the solenoid if it is filled with air? The flux linking the coils of the solenoid is I a A N NBA d N = = = 2 B A B The factor multiplying I is a collection of constants and geometrical factors--this is the self inductance. a A N L 2 = 7 Example (30.45): Determine the self-inductance of the toroidal solenoid shown in the figure. r I N B 2 = For a toroid: Determine the flux through a cross-section: = = = = = = = = a b Ih N dydx x I N dA r I N d h y y b x a x ln 2 2 2 B A B 8 Example continued I a b h N = ln 2 B To find L, compare this result LI N = to = a b h N L ln 2 2 Find that 9 An inductor is essentially a coil of wire. An inductor is essentially a coil of wire....
View Full Document

Page1 / 37

chapter30---PHY 131 JAB - 1 Chapter 30: Inductance 2 Coil 1...

This preview shows document pages 1 - 10. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online