PHY_solution-chapter24

PHY_solution-chapter24 - 24.1: Q= CV = 25.0 V )(7.28 F) =...

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24.1: . C 10 82 . 1 ) F 28 . 7 )( V 0 . 25 ( 4 - × = = = μ CV Q 24.2: a) pF. 29 . 3 m 00328 . 0 m 00122 . 0 2 0 0 = = = ε d A ε C b) . kV 2 . 13 F 10 29 . 3 C 10 35 . 4 12 8 = × × = = - - C Q V c) . m V 10 02 . 4 m 00328 . 0 V 10 2 . 13 6 3 × = × = = d V E 24.3: a) . V 604 F 10 45 . 2 C 10 148 . 0 10 6 = × × = = - - C Q V b) . m 0091 . 0 m) 10 328 0 F)( 10 45 . 2 ( 2 0 3 10 0 = × × = = - - ε . ε Cd A c) . m V 10 84 . 1 m 10 328 . 0 V 604 6 3 × = × = = - d V E d) . C/m 10 63 . 1 ) m V 10 84 . 1 ( 2 5 6 0 0 0 - × = × = = = ε E ε σ ε σ E 24.4: d ε σ Ed V 0 = = 2 2 12 2 12 Nm C 10 85 . 8 ) m 00180 . 0 )( m C 10 60 . 5 ( - - × × = =1.14 mV 24.5: a) μC CV Q 120 = = b) d A ε C 0 = C 60 2 and 2 means 2 μ Q Q C C d d = c) C 480 4 and , 4 , 4 means 2 μ Q Q C C A A r r = 24.6: 12.0 V since the plates remain charged. (a) (i) (b) C Q V = Q does not change since the plates are disconnected from the battery. d ε C A = If d is doubled, V 0 . 24 2 so , 2 1 = V V C C (ii) C C A A r r πr A 4 and , 4 then , 2 if so , 2 = which means that 670d2b2a3d53ad6eb009a441a9cd070db2d4ad4a.doc Page 1 of 23
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V 00 . 3 4 1 = V V 24.7: Estimate cm 0 . 1 = r mm 8 . 2 F 10 00 . 1 ) m 010 . 0 ( so 12 2 0 2 0 0 = × = = = - π ε C πr d d A ε C ε The separation between the pennies is nearly a factor of 10 smaller than the diameter of a penny, so it is a reasonable approximation to treat them as infinite sheets. 24.8: (a) Ed V = cm 00 . 1 m 10 ) C N 10 ( V 100 2 4 = = = - d d d R ε d A ε C 2 0 0 π = = 0 0 4 4 πε Cd πε Cd R = = ) C Nm 10 9 )( m 10 )( F 10 00 . 5 ( 4 2 2 9 2 12 × × = - - R cm 24 . 4 m 10 24 . 4 2 = × = - R (b) pC 500 ) V 100 )( pF 5 ( = = = CV Q 24.9: a) ) ( ln 2 0 a b r r πε L C = F 10 35 . 4 ) 50 . 0 00 . 5 ( ln 2 ) m 180 . 0 ( 12 0 - × = = πε C b) V 30 . 2 ) F 10 35 . 4 /( ) C 10 0 . 10 ( / 12 12 = × × = = - - C Q V 24.10: a) . 84 . 5 77 . 1 m F 10 5 . 31 2 2 ) ( ln ) ( ln 2 12 0 0 0 = = × = = = - a b a b a b r r πε L C πε r r r r πε L C b) . m C 10 19 . 8 ) m F 10 5 . 31 )( V 60 . 2 ( 11 12 - - × = × = = L C V L Q 24.11: a) F/m. 10 56 . 6 ) mm 5 . 1 / mm 5 . 3 ( ln 2 ) ( ln 2 11 0 0 - × = = = πε r r πε L C a b The b) charge on each conductor is equal but opposite. Since the inner conductor is at a higher potential it is positively charged, and the magnitude is: 670d2b2a3d53ad6eb009a441a9cd070db2d4ad4a.doc Page 2 of 23
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C. 10 43 . 6 ) mm 1.5 mm 5 . 3 ( ln ) V 35 . 0 )( m 8 . 2 ( 2 ) ( ln 2 11 0 0 - × = = = = ε r r LV ε CV Q a b π 24.12: For two concentric spherical shells, the a) capacitance is: a a b b a a b a b b a r kC kCr r r r kCr kCr r r r r k C - = = - - = 1 . m 175 . 0 m 150 . 0 ) F 10 116 ( ) m 150 . 0 )( F 10 116 ( 12 12 = - × × = - - k k r b b) . C 10 55 . 2 ) V 220 )( F 10 116 ( and , V 220 8 12 - - × = × = = = CV Q V 24.13 : a) . F 10 94 . 8 m 125 . 0 m 148 . 0 ) m
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PHY_solution-chapter24 - 24.1: Q= CV = 25.0 V )(7.28 F) =...

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