PHY_solution-chapter28

PHY_solution-chapter28 - 28.1: For a charge with velocity ,...

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Unformatted text preview: 28.1: For a charge with velocity , ) s m 10 8.00 ( 6 j v = the magnetic field produced at a position r away from the particle is . 4 2 r q r v B = So for the cases below: a) 4 1 2 , ) m 0.500 ( =- = + = r k r v i r . ) T 10 1.92 ( ) m 0.50 ( ) s m 10 8.0 )( C 10 (6.0 4 4 5 2 6 6 2 k k k k B B r qv - - = - =- = -- b) . ) m 0.500 ( = = - = B r v j r c) . 4 1 , ) m 0.500 ( 2 = + = = r i r v k r . 4 i i B 2 B r qv = + = d) 2 2 2 1 , ) m 0.500 ( ) m 0.500 ( r r = =- = +- = i r v k j r 2 2 2 2 2 4 i B B r qv + = + = + = i i B 2 28.2: + = + = 2 2 total 4 d v q d qv B B B page. the into T, 10 38 . 4 ) m 120 . ( ) s m 10 . 9 )( C 10 . 3 ( ) m 120 . ( ) s m 10 5 . 4 )( C 10 . 8 ( 4 4 2 6 6 2 6 6--- = + = B B 28.3: 3 4 r q r v B = a) ; , i r i v r v = = , = = B r v b) ; , j r i v r v = = m 0.500 , = = r vr k r v k B ) T 1.31 ( so negative, is T 10 1.31 ) m 0.500 ( ) s m 10 6.80 )( C 10 4.80 )( C s N 10 1 4 6 6 2 5 6 2 2 7 2---- - = = = = q r v q B c) ); )( m 0.500 ( , j i r i v + = = v m 0.7071 , ) m 0.500 ( = = r v k r v ( 29 k B ) T 10 4.62 ( ; T 10 4.62 ) m 0.7071 ( ) s m 10 6.80 )( m 0.500 ( C) 10 4.80 )( C s N 10 1 4 7 7 3 5 6 2 2 7 3---- - = = = = B r r v q B d) ; , k r i v r v = = m 0.500 , =- = r vr j r v j B T) 10 1.31 ( ; T 10 1.31 m) 0.500 ( ) s m 10 6.80 )( C 10 4.80 )( C s N 10 1 4 6 6 2 5 6 2 2 7 2---- = = = = B r v q B 02049bb671f86d954bb3d2f668918d9b13d6cc69.doc Page 1 of 25 28.4: Following Example 28.1 we can find a) the magnetic force between the charges: down). points charge lower the on force the and up points charge upper the on force (the N 10 1.69 ) m 0.240 ( ) s m 10 9.00 )( s m 10 4.50 )( C 10 3.00 )( C 10 8.00 ( ) A m T 10 ( 4 3 2 6 6 6 6 7 2---- = = = r v v q q F B The Coulomb force between the charges is N 3.75 ) C m N 10 8.99 ( 2 2 12 m) (0.240 C 10 0) (8.00)(3.0 2 2 9 = = =- 2 2 1 r q q k F (the force on the upper charge points up and the force on the lower charge points down). The ratio of the Coulomb force to the magnetic force is 2 1 2 v v c = =- 3 N 10 1.69 N 3.75 10 2.22 3 . The magnetic b) forces are reversed when the direction of only one velocity is reversed but the magnitude of the force is unchanged....
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This note was uploaded on 02/25/2009 for the course PHY 127 taught by Professor Mr.yang during the Spring '08 term at SUNY Stony Brook.

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PHY_solution-chapter28 - 28.1: For a charge with velocity ,...

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