Data and Calculations:
Unknown Mineral # M3852
Part B:
Mass of Crucible = 19.4702 g
Mass of vial with mineral = 14.7092 g
Mass of dehydrated sample + mass of crucible = 19.8721 g
Mass of vial with mineral 
mass of mineral sample = 13.8939 g
Mass of dehydrated sample = .4019 ± .001 g
Mass of water loss = .4134
± .002 g
Column1
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Column3
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Column6
Lower Limit
Mass
Upper Limit
Weight of vial w/sample
14.7087 g
14.7092 g
14.7097 g
Vial weight  sample weight
13.8934 g
13.8939 g
13.8944 g
Weight of sample
.8143 g
.8153 g
0.8163 g
(Upper limit weight of vial w
(Lower limit weight of (vial weight  sampl
(Upper limit of weight of s
[Use inverse limits to find lo
Column1
Column2
Column3
Column4
Column5
Column6
Column7
Lower Limit
Weight
Upper Limit
Weight of sample
.8143 g
.8153 g
.8163 g
Calculated sa
Weight of dehydrated sample
.4009 g
.4019 g
.4029 g
Water weight loss
.4114 g
.4134 g
.4154 g
Mass of mineral sample = .8153 ± .001 g
Upper and Lower Masses
from observed ma
G
H20
= (grams of water)/(grams of mineral) = (.4134 g water)/(.8153 g mineral) =
.507 g water/ g mineral
Upper G
H2
0
= (Upper limit weight loss)/(Lower limit sample) = (.4154 g water)/(.8143 g mineral) =
.510 g water/g mineral
Lower GH
20
= (Lower limit weight loss)/(Upper limit sample) = (.4114 g water)/(.8163 g mineral) =
.504 g water/g mineral
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View Full DocumentPart C:
Mass of vial with mineral = 13.8960 ± .0005 g
Mass of vial with mineral 
mass of mineral sample = 13.6810 ± .0005 g
Mass of crucible = 22.7711 ±.0005g
Mass of mineral sample = .215 ± .001 g
M
H20
= (G
H20
)/(18 g /mol) =
2.82 x 10
2
moles water/g mineral
Upper M
H20
= (Upper G
H20
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 Fall '08
 MICHAELH.HECHT,ROBERTP.L'ESPERANCE
 Chemistry

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