# HW3_Soln - HW3 Solution 4.1(a VG > VTN corresponds to the...

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HW3 Solution 4.1 (a) V G > V TN corresponds to the inversion region (b) V G << V TN corresponds to the accumulation region (c) V G < V TN corresponds to the depletion region 4.2 (a) C ox " = ε ox T ox = 3.9 ε o T ox = 3.9 8.854 x 10 14 F / cm ( ) 50 x 10 9 m 100 cm / m ( ) = 6.91 x 10 8 F cm 2 = 69.1 nF cm 2 (b), (c) & (d): Scaling the result from part (a) yields C ox " = 69.1 nF cm 2 50 nm 20 nm = 173 nF cm 2 | C ox " = 69.1 nF cm 2 50 nm 10 nm = 346 nF cm 2 | C ox " = 69.1 nF cm 2 50 nm 20 nm = 691 nF cm 2 4.3 C d = ε s 2 ε s qN B 0.75 V ( ) = 11.7 8.854 x 10 14 F / cm ( ) 2 11.7 ( ) 8.854 x 10 14 F / cm ( ) 1.602 x 10 19 10 15 / cm 3 ( ) 0.75 V ( ) = 10.5 x 10 9 F / cm 2 4.12 ( a ) I = 100 μ A V 2 10 1 5 0.75 0.5 2 0.5 = 2.00 mA ( b ) I = 100 μ A V 2 10 1 3 0.75 0.2 2 0.2 = 430 μ A 4.13 a ( ) V GS = V G V S = 5 − − 0.5 ( ) = 5.5 V V DS = V D V S = 0 − − 0.5 ( ) = 0.5 V I = I S = − 100 μ A V 2 10 1 5.5 0.75 0.5 2 0.5 = − 2.25 mA b ( ) V GS = V G V S = 3 − − 1 ( ) = 4 V V DS = V D V S = 0 − − 1 ( ) = 1 V I = I S = − 100 μ A V 2 10 1

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