HW3_Soln

HW3_Soln - HW3 Solution 4.1 (a) VG > VTN corresponds to...

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HW3 Solution 4.1 (a) V G > V TN corresponds to the inversion region (b) V G << V TN corresponds to the accumulation region (c) V G < V TN corresponds to the depletion region 4.2 (a) C ox " = ε ox T ox = 3.9 o T ox = 3.9 8.854 x 10 14 F / cm () 50 x 10 9 m 100 cm / m = 6.91 x 10 8 F cm 2 = 69.1 nF cm 2 (b), (c) & (d): Scaling the result from part (a) yields C ox " = 69.1 nF cm 2 50 nm 20 nm = 173 nF cm 2 | C ox " = 69.1 nF cm 2 50 nm 10 nm = 346 nF cm 2 C ox " = 69.1 nF cm 2 50 nm 20 nm = 691 nF cm 2 4.3 C d = s 2 s qN B 0.75 V = 11.7 8.854 x 10 14 F / cm ( ) 2 11.7 8.854 x 10 14 F / cm 1.602 x 10 19 10 15 / cm 3 0.75 V = 10.5 x 10 9 F / cm 2 4.12 ( a ) I = 100 μ A V 2 10 1 5 0.75 0.5 2 0.5 = 2.00 mA ( b ) I = 100 A V 2 10 1 3 0.75 0.2 2 0.2 = 430 A 4.13 a V GS = V G V S = 5 −− 0.5 = 5.5 V V DS = V D V S = 0 0.5 ( ) = 0.5 V I = I S =− 100 A V 2 10 1 5.5 0.75 0.5 2 0.5 2.25 mA b V GS = V G V S = 3 1 =4 V V DS = V D V S = 0 1 = 1 V I = I S 100 A V 2 10 1 4 0.75 1 2
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This note was uploaded on 03/02/2009 for the course ECE 137a taught by Professor Staff during the Winter '08 term at UCSB.

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HW3_Soln - HW3 Solution 4.1 (a) VG &gt; VTN corresponds to...

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