This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Explicit the magnitude and the direction of the torque. (4pts) Torque1 = 0.4 m x 30 N = 12Nm Direction : counter clockwise (2) Calculate the torque on the rod from the force F2. Express answer in Nm. Explicit the magnitude and the direction of the torque. (4pts) Torque2 = 1.2 m x 15 N = 18Nm Direction : clockwise (3) If another force ( F3 ) would be applied to the position 0.8m away from the rotating axis to make the rod equilibrium, which way of the direction F3 should be? Up or Down? (3pts) Up : In order to make it in equilibrium, the net torque should be zero. Torque1 + Torque2 is clockwise direction (Torque2>Torque1). We need counter clockwise torque. (4) Calculate the magnitude of F3. (4pts) Torque1 + Torque2 + Torque3 = 0 12Nm 18Nm + Torque3 =0, Torque3 = 6Nm, F3=Torque3/0.8m = 7.5N...
View
Full
Document
This note was uploaded on 04/29/2008 for the course PS 303 taught by Professor Modi during the Spring '08 term at University of Texas at Austin.
 Spring '08
 MODI

Click to edit the document details