This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: Explicit the magnitude and the direction of the torque. (4pts) Torque1 = 0.4 m x 30 N = 12Nm Direction : counter clockwise (2) Calculate the torque on the rod from the force F2. Express answer in Nm. Explicit the magnitude and the direction of the torque. (4pts) Torque2 = 1.2 m x 15 N = 18Nm Direction : clockwise (3) If another force ( F3 ) would be applied to the position 0.8m away from the rotating axis to make the rod equilibrium, which way of the direction F3 should be? Up or Down? (3pts) Up : In order to make it in equilibrium, the net torque should be zero. Torque1 + Torque2 is clockwise direction (Torque2>Torque1). We need counter clockwise torque. (4) Calculate the magnitude of F3. (4pts) Torque1 + Torque2 + Torque3 = 0 12Nm -18Nm + Torque3 =0, Torque3 = 6Nm, F3=Torque3/0.8m = 7.5N...
View Full Document
- Spring '08
- Force, NM, net torque, counter clockwise torque