This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Morby, Grant Quiz 4 Due: May 3 2006, 11:00 pm Inst: Drummond 1 This printout should have 18 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points A synchronous satellite, which always re mains above the same point on a planets equator, is put in orbit about a planet similar to Jupiter. This planet rotates once every 5 . 3 h, has a mass of 1 . 9 10 27 kg and a radius of 6 . 99 10 7 m. Given that G = 6 . 67 10 11 Nm 2 / kg 2 , calculate how far above Jupiters surface the satellite must be. Correct answer: 3 . 54316 10 7 m. Explanation: Basic Concepts: Solution: According to Keplers third law: T 2 = 4 2 GM r 3 where r is the radius of the satellites orbit. Thus, solving for r r = G M T 2 4 2 1 3 = { 6 . 67 10 11 Nm 2 / kg 2 } 1 3 (1 . 9 10 27 kg)(19080 s) 2 4(3 . 1415926536 ) 2 1 3 = 1 . 05332 10 8 m . Now, the altitude h of the satellite (measured from the surface of Jupiter) is h = r R = (1 . 05332 10 8 m) (6 . 99 10 7 m) = 3 . 54316 10 7 m . 002 (part 1 of 1) 10 points It is found that a 5 m segment of a long string contains 3 complete wavelengths and has a mass of 190 g. At one point it is vibrating sinusoidally with a frequency of 53 Hz and a peak to valley displacement of 0 . 74 m. What power is being transmitted along the string? Correct answer: 25479 . 6 W. Explanation: since k 2 , 2 f , v k , P = 1 2 2 A 2 v = 1 2 M L 2 A 2 k = 25479 . 6 W . 003 (part 1 of 1) 10 points At t = 0, a transverse wave pulse in a wire is described by the function y = 5 e x 2 / 2 , where x and t are given in SI units. Which of the following functions describes this wave if it is traveling in the negative x direction with a speed of 4 . 5 m / s . 1. y = 5 e x 2 / 2 2. y = 5 e ( x +4 . 5 t ) 2 / 2 correct 3. y = 5 e ( x 2 +4 . 5 t ) / 2 4. y = 5 e ( x 2 4 . 5 t ) / 2 5. y = 5 e x 2 / 2 + 4 . 5 t 6. y = 5 e ( x 4 . 5 t ) 2 / 2 7. y = 5 e x 2 / 2 4 . 5 t Explanation: For the wave traveling in the negative di rection with the speed of 4 . 5 m / s , we need to replace x with x + 4 . 5 t which gives y = 5 e ( x +4 . 5 t ) 2 / 2 . 004 (part 1 of 1) 10 points The length of a hollow pipe is 43 . 2 cm. There is a standing wave in the pipe with a wavelength of 19 . 2 cm. Morby, Grant Quiz 4 Due: May 3 2006, 11:00 pm Inst: Drummond 2 Which figure schematically represents this standing wave? 1. 2. 3. 4. 5. 6. correct 7. 8. 9. 10. Explanation: Let : N = number of nodes = 19 . 2 cm , and = 43 . 2 cm ....
View
Full
Document
 Spring '09
 KLEINMAN
 Physics

Click to edit the document details