# HW33 - homework 33 PAPAGEORGE MATT Due 4:00 am Question 1...

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homework 33 – PAPAGEORGE, MATT – Due: Apr 19 2008, 4:00 am 2 = (2 . 8 kg) (9 . 8 m / s 2 ) (25 m / s) 2 = 0 . 043904 kg / m . The velocity is v 2 = radicalBigg F μ , so v 1 = radicalbigg m 2 g μ (2) = radicalBigg (3 kg) (9 . 8 m / s 2 ) 0 . 043904 kg / m = 25 . 8775 m / s . AlternateSolution: Plugging μ from Eq. 1 into Eq. 2, we have v 1 = radicalbigg m 2 g μ (2) = radicalBigg m 2 g v 2 1 m 1 g = v 1 radicalbigg m 2 m 1 (3) = (25 m / s) radicalBigg (3 kg) (2 . 8 kg) = 25 . 8775 m / s . Question 4, chap 16, sect 2. part 1 of 3 10 points A sonar signal of frequency 2 . 05 × 10 6 Hz has a wavelength of 1 . 68 mm in water.
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