HW 33 - Morby, Grant Homework 33 Due: Apr 26 2006, noon...

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Unformatted text preview: Morby, Grant Homework 33 Due: Apr 26 2006, noon Inst: Drummond 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points A transverse wave in a wire has form y ( x,t ) = (1 . 6 cm) sin h (5 . 08 m- 1 ) x- (7110 s- 1 ) t i The wire has linear density = 7 . 59 g / m. What is its tension? Correct answer: 14868 N. Explanation: A sinusoidal transverse wave of the general form y ( x,t ) = A sin( kx- t ) travels in the positive x direction at speed v = k . For the wave in question, this speed is v = 7110 s- 1 5 . 08 m- 1 = 1399 . 61 m / s . For a transverse wave in a wire, this speed fol- lows from the wires tension and linear density according to v = s F , hence F = v 2 = 14868 N . 002 (part 1 of 1) 10 points A harmonic wave y = A sin[ k x- t- ] , where A = 1 meter, k has units of m- 1 , has units of s- 1 , and has units of radians, is plotted in the diagram below. +1- 1 A (meters) x (meters) 10 m 20 m 30 m At the time t = 0 Which wave function corresponds best to the diagram? 1. y = A sin 2 15 m x- t- 4 3 2. y = A sin 2 3 m x- t- 2 3 3. y = A sin 2 9 m x- t- 5 3 4. y = A sin 2 9 m x- t- 2 3 5. y = A sin 2 3 m x- t- 1 3 6. y = A sin 2 9 m x- t- 4 3 7. y = A sin 2 3 m x- t- 4 3 8. y = A sin 2 15 m x- t- 1 3 correct 9. y = A sin 2 15 m x- t- 2 3 10. y = A sin 2 15 m x- t- 5 3 Explanation: From the diagram of the wave function the wave-length = 15 m (6 horizontal scale di- visions of 2 . 5 m each, see diagram below). Notice: Since one wave-length is 2 ra- dians, each horizontal division is 2 6 = 3 radians. Morby, Grant Homework 33 Due: Apr 26 2006, noon Inst: Drummond 2 The given wave function (sine function with t = 0) y = A sin k x- = A sin 2 x- = A sin 2 15 m x- (dark curve in diagram below) is shifted 1 divisions to the right (negative phase shift) of a no-phase-shift sine function y = sin 2 15 m x (gray curve in diagram below), therefore = 1 3 = 1 3 radians ....
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This note was uploaded on 03/02/2009 for the course PHY 58235 taught by Professor Kleinman during the Spring '09 term at University of Texas at Austin.

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HW 33 - Morby, Grant Homework 33 Due: Apr 26 2006, noon...

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