# answerkey7 - τ = r × F F = τ/r = 40 N 4 m = 100 N 10 120...

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Answer Key for problems in Unit VII. 2. (-8N, 0) + (0,3N) = (-8N, 3N) magnitude of that force = q ( - 8) 2 + 3 2 = 8 . 544. 3. F C = (4 . 0 N, 5 . 5 N ) in rectangular coordinate F c = (6 . 8 N,N 53 . 97 o E ) 4. Resultant Force = (6N,0) + (0,8N) + (0,-14N) = (6N,-6N) It is not in equilibrium because the net force is not zero. 5. Skip it. 6. mg = 13 N 6 N = μmg = μ × 13 N , μ = 6 / 13 F = μ (13 N + 8 N ) = 6 / 13 × 21 N = 9 . 69 N 7. F = μmg , μ = F/mg = 5 N/ 20 N = 0 . 25. 9. τ = 40 N · m ,
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Unformatted text preview: τ = r × F , F = τ/r = 40 N/ . 4 m = 100 N . 10. 120 lb. 451 N/ 1 lb = 534 N , 50 lb = 4 . 451 N/ 1 lb = 222 . 5 N 7 ft = 2 . 1336 m . τ d = 2 . 1336 m × 222 . 5 N = 474 . 726 N · m , τ m = r × 534 N In order to be balanced, magnitudes of two τ s are same. r = 474 . 726 N · m/ 534 N = 0 . 889 m . 1...
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