Exam Review 1 - q = the frequency of the recessive...

Info iconThis preview shows pages 1–10. Sign up to view the full content.

View Full Document Right Arrow Icon
Exam 1 review
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 2
Mitosis versus meiosis http://www.pbs.org/wgbh/nova/baby/me dia/divi.swf
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Codominance in blood
Background image of page 4
Evolution Natural selection vs. genetic drift Bottleneck effect, founder effects
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 6
A founder effect occurs when a new colony is started by a few members of the original population. This small population size means that the colony may have: * reduced genetic variation from the original population. * a non-random sample of the genes in the original population. Founder effects
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Hardy-Weinberg p 2 + 2pq + q 2 p = the frequency of the dominant allele (represented here by A)
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 10
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: q = the frequency of the recessive allele (represented here by a) p2 = frequency of AA (homozygous dominant) 2pq = frequency of Aa (heterozygous) q2 = frequency of aa (homozygous recessive) • Your answer: 0.4 • Answer: • You should expect 160 to be homozygous dominant. • Calculations: • q2 for this population is 360/1000 = 0.36 • q = = 0.6 • p = 1 - q = 1 - 0.6 = 0.4 • The homozygous dominant frequency = p2 = (0.4)(0.4) = 0.16. • Therefore, you can expect 16% of 1000, or 160 individuals, to be homozygous dominant....
View Full Document

{[ snackBarMessage ]}

Page1 / 10

Exam Review 1 - q = the frequency of the recessive...

This preview shows document pages 1 - 10. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online