real_analysis_homework6

real_analysis_homework6 - Real Analysis II Homework 6 H´...

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Unformatted text preview: Real Analysis II Homework 6 H´ ector Guillermo Cu´ ellar R´ ıos March 30, 2006 19.2 (b) The set of subsequential limits of a bounded sequence is always non- empty. True by Corollary 19.12. (c) ( s n ) converges to s iff lim inf s n = lim sup s n = s True by third paragraph in Definition 19.9 and exercise 19.9. (d) Let ( s n ) be a bounded sequence and let m = lim sup s n . Then for every ε > 0 there are infinitely many terms in the sequence greater than m- ε True by Theorem 19.11(b) 19.3 For each sequence, find the set S of subsequential limits, the limit superior, and the limit inferior. (a) s n = (- 1) n S = {- 1 , 1 } lim sup s n = 1 lim inf s n =- 1 (c) u n = n 2 [- 1 + (- 1) n ] S = {-∞ , } lim sup u n = 0 lim inf u n =-∞ 19.4 Let ( s n ) be a bounded sequence and suppose that lim inf s n = lim sup s n = s . Prove that ( s n ) is convergent and that lim s n = s . (a) w n = (- 1) n n S = { } lim sup w n = 0 lim inf w n = 0 (d) z n = (- n ) n S = {-∞ , + ∞} lim sup z n = + ∞ lim inf z n =-∞ 19.5 Use exercise 18.14 to find the limit of each sequence. 1 (a) s n = ( 1 + 1 2 n ) 2 n s n = ( 1 + 1 2 n ) 2 n → e since it is a subsequence of the sequence s n = ( 1 + 1 n ) n (b) s n = ( 1 + 1 n ) 2 n ( 1 + 1 n ) 2 n = ( 1 + 1 n ) n ( 1 + 1 n ) n since each sequence is converging to e , then by Theorem 17.1(c), then by Theorem 17....
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real_analysis_homework6 - Real Analysis II Homework 6 H´...

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