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Physics106Lab- #8

Physics106Lab- #8 - Weight 1 = 50 g Length 3 = 42.5 cm...

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James Wong Forces on a Strut 12/04/08 Physics 106A-005 Objective The purpose of this lab is to determine the tension on the supporting cord and a strut by taking torques about the pivot point of the strut. Setup First we begin our experiment by attaching the apparatus onto the table pole. Then we proceed to attach a string onto the pulley. One end of the string has a weight holder attached to it, and the other end of the string is wrapped around a iron pole. The weight holder and the iron pole are to be in equilibrium to each other on the pulley, so we proceed to add weights onto the weight holder and the iron pole until they are in equilibrium. We then concluded the experiment by recording the masses that were attached to the system, and the lengths of where the masses were attached. Formulas t = r x F mg(r/2)sinθ = t mg(r)(sinθ)= t mg(r)(sin γ) = t Data Weight of strut = 113.6 g Length 1 = 33 cm Weight = 615 g Length 2 = 48.5 cm
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Unformatted text preview: Weight 1 = 50 g Length 3 = 42.5 cm Weight 2 = 270 g Total Length = 58.5 cm Θ = 44.2 Calculations T for Center = 113.6(9.8)(0.585/2)(sin(44.2)) = 227.02 T for Weight 1 = (50)(9.8)(0.33)(sin(44.2)) = 112.73 T for Weight 2 = (270)(9.8)(0.485)(sin(44.2)) = 556.64 Conclusions In this experiment, we can see how greatly the torque can greatly change due to the mass and the radius. Depending on where you place the mass, the more or less the torque there will be. When one sets the mass closer to the center of the length, the less torque there will be. The further away the mass is from the center, the more torque there will be. When we perform the experiment, we noticed that even though the strut is in equilibrium, one small tab on the strut could set it out of the equilibrium. So when we record the data, the system might not truly be in equilibrium, and thus could cause an error in our results....
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