204ps32006sols

# 204ps32006sols - Economics 204 August 2006 1...

• Notes
• 5

This preview shows pages 1–3. Sign up to view the full content.

Problem Set 3 Economics 204 - August 2006 1. Connectedness (a) Suppose we define two sets as being separated if neither contains a limit point of the other and that a set in a metric space is connected if it cannot be written as the union of two disjoint non-empty separated sets. Prove that this definition is equivalent to the one given in lecture. To avoid confusion we will refer to the definition of ‘separated’ and ‘connected’ from the textbook as text-separated and text-connected and the definitions intro- duced here will be referred to as ps-separated and ps-connected . It is tempting to try to show that ps -separated equivalent to the text -separated. If we could show this, because all text -separated are disjoint we would know that the two definitions of connected are equivalent. However, the two definitions of separated are not equivalent. An isolated point of a set is not a limit point. Thus, if A and B have an isolated point in common (e.g. A = (0 , 1) ∪ { 2 } and B = { 2 } ∪ (3 , 4)) they can be ps -separated but not disjoint (and therefore not text -separated). The definition of ps -connected excludes this possiblity by specifying that the separated sets must be disjoint. Now proceed with the proof that a set is ps -connected if and only if it is text -connected by showing that two disjoint sets A and B are ps -separated if and only if they are text -separated. Proof: ( ) We will prove the contrapositive. Suppose that A and B are not text -separated. Without loss of generality, suppose that that there exists an x A cl B . Because x cl B , for all > 0 there exists b B ( x ) B . This means that either x is a limit point or an isolated point of B . If it is a limit point then we are done, because this means that A contains a limit point of B and therefore A and B are not ps -separated. If x an isolated point of B , it cannot be an isolated point of A , because the sets are disjoint. This means that x must be a limit point of A , so B contains a limit point of A and the sets cannot be ps -separated. ( ) Again we prove the contrapositive. Suppose that the sets are not ps -separated. Without loss of generality, suppose that there exists a b L A which is a limit point of B . By definition, for all > 0, B ( b L ) contains some element of B , so it also must be in the closure of B . Therefore A cl B = so A and B are not text -separated. (b) Suppose that the sets C and D are two non-empty separated subsets of X whose union is X and Y is a connected subset of X . Prove that Y lies entirely within C or D . Proof: Being separated, C and cl D must be disjoint as must be cl C and D . The sets cl C Y and D Y must also be disjoint and their union is Y so they are a separation of Y and the same goes for C Y and cl D Y . For each of these pairs, both sets being non-empty contradicts the fact that Y is connected. Therefore 1

This preview has intentionally blurred sections. Sign up to view the full version.

one of them is empty. Therefore Y lies entirely within C or
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern