01_InstSolManual_PDF_Part10

01_InstSolManual_PDF_Part10 - 21 sin 198° 2 5 A x 5 1 69...

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1.40. Set Up: In each case the direction of the vector is specified by the angle measured counterclockwise from the axis. The components are calculated as: Solve: (a) The sketch of the vector and its components in Figure 1.40a shows that both components are positive and that Figure 1.40 (b) Figure 1.40b shows that is negative, is positive and (c) Figure 1.40c shows that is posi- tive, is negative and (d) Figure 1.40d shows that both and are negative and 1.41. Set Up: In each case, create a sketch (Figure 1.41) showing the components and the resultant to determine the quadrant in which the resultant vector lies. The component vectors add to give the resultant. Figure 1.41 A y A x y x A ( a ) A y A x y x A ( b ) f u u O O A S 0 A x 0 . 0 A y 0 . A y A x 2 21 km. A y 5 1 69 km 21
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Unformatted text preview: 21 sin 198° 2 5 A x 5 1 69 km 21 cos 198° 2 5 2 66 km; u 5 1 1.1 p rad 21 180° / p rad 2 5 198°; A x . A y . A y A x A y 5 1 254 lb 21 sin 325° 2 5 2 146 lb. A x 5 1 254 lb 21 cos 325° 2 5 208 lb; A x . A y . A y A x 1 37.5 m / s. A y 5 1 75 m / s 21 sin 150° 2 5 A x 5 1 75 m / s 21 cos 150° 2 5 2 65.0 m / s; u 5 1 5 p / 6 rad 21 180° / p rad 2 5 150°; A A A y A y A x A x O O y x x ( c ) ( d ) 325 ° 198 ° 60 ° 150 ° A A A y A y A x A x O O y y x x ( a ) ( b ) A y . A x . A y 5 1 50.0 N 21 sin 60° 2 5 1 43.3 N. A x 5 1 50.0 N 21 cos 60° 2 5 1 25.0 N; A y 5 A sin u . A x 5 A cos u ; 1 x u 1-10 Chapter 1...
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