01_InstSolManual_PDF_Part13

# 01_InstSolManual_PDF_Part13 - Models Measurements and...

• Notes
• 1

This preview shows page 1. Sign up to view the full content.

Solve: (a) (b) The resultant vector thus makes an angle of counterclockwise from the axis. (c) (d) The resultant vector thus makes an angle of counterclockwise from the axis. Reflect: Note that has a larger magnitude than Vector addition is very different from addition of scalars. 1.46. Set Up: Use coordinates where is east and is north. and are the two given displacements (Figure 1.46a). Displacement makes an angle of counterclockwise from the axis. Calculate Figure 1.46 Solve: (a) and or south of east, as shown in Figure 1.46b. (b) The vector addition diagram for is given in Figure 1.46c. The magnitude and direction of in this diagram agrees with our calculation using components. R S R S 5 A S 1 B S f 5 19° u 5 341°; tan u 5 2 53.7 mi 155.8 mi R 5 " R x 2 1 R y 2 5 " 1 155.8 mi 2 2 1 1 2 53.7 mi 2 2 5 165 mi; R y 5 A y 1 B y 5 31.8 mi 1 1 2 85.5 mi 2 5 2 53.7 mi R x 5 A x 1 B x 5 78.8 mi 1 77.0 mi 5 155.8 mi; B y 5 B sin 312° 5 1 115 mi 21 sin 312° 2 5 2 85.5 mi B x 5 B cos 312° 5 1 115 mi 21 cos 312° 2 5 77.0 mi; A y 5 A sin
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 5 A sin 22° 5 1 85 mi 21 sin 22° 2 5 31.8 mi. A x 5 A cos 22° 5 1 85 mi 21 cos 22° 2 5 78.8 mi; N N W W S S B B A A E E y x 312 ° 22 ° 48 ° 85 mi 115 mi ( a ) ( c ) ( b ) R y R R R x y x u f R S 5 A S 1 B S . 1 x u 5 312° B S B S A S 1 y 1 x B S 1 A S . B S 2 A S 1 x 295.0° u 5 tan 2 1 31 2 6.00 cm 2 / 1 2.80 cm 24 5 2 65.0°. R 5 "1 2.80 cm 2 2 1 1 2 6.00 cm 2 2 5 6.62 cm; 2 6.00 cm R y 5 B y 1 1 2 A y 2 5 2 3.75 cm 1 1 2 2.25 cm 2 5 R x 5 B x 1 1 2 A x 2 5 4.10 cm 1 1 2 1.30 cm 2 5 2.80 cm; 1 x 344.5° u 5 tan 2 1 31 2 1.50 cm 2 / 1 5.40 cm 24 5 2 15.5°. R 5 " R x 2 1 R y 2 5 "1 5.40 cm 2 2 1 1 2 1.50 cm 2 2 5 5.60 cm; R y 5 A y 1 B y 5 2.25 cm 1 1 2 3.75 cm 2 5 2 1.50 cm R x 5 A x 1 B x 5 1.30 cm 1 4.10 cm 5 5.40 cm; Models, Measurements, and Vectors 1-13...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern