01_InstSolManual_PDF_Part13 - 5 A sin 22° 5 1 85 mi 21 sin...

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Solve: (a) (b) The resultant vector thus makes an angle of counterclockwise from the axis. (c) (d) The resultant vector thus makes an angle of counterclockwise from the axis. Reflect: Note that has a larger magnitude than Vector addition is very different from addition of scalars. 1.46. Set Up: Use coordinates where is east and is north. and are the two given displacements (Figure 1.46a). Displacement makes an angle of counterclockwise from the axis. Calculate Figure 1.46 Solve: (a) and or south of east, as shown in Figure 1.46b. (b) The vector addition diagram for is given in Figure 1.46c. The magnitude and direction of in this diagram agrees with our calculation using components. R S R S 5 A S 1 B S f 5 19° u 5 341°; tan u 5 2 53.7 mi 155.8 mi R 5 " R x 2 1 R y 2 5 " 1 155.8 mi 2 2 1 1 2 53.7 mi 2 2 5 165 mi; R y 5 A y 1 B y 5 31.8 mi 1 1 2 85.5 mi 2 5 2 53.7 mi R x 5 A x 1 B x 5 78.8 mi 1 77.0 mi 5 155.8 mi; B y 5 B sin 312° 5 1 115 mi 21 sin 312° 2 5 2 85.5 mi B x 5 B cos 312° 5 1 115 mi 21 cos 312° 2 5 77.0 mi; A y 5 A sin
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Unformatted text preview: 5 A sin 22° 5 1 85 mi 21 sin 22° 2 5 31.8 mi. A x 5 A cos 22° 5 1 85 mi 21 cos 22° 2 5 78.8 mi; N N W W S S B B A A E E y x 312 ° 22 ° 48 ° 85 mi 115 mi ( a ) ( c ) ( b ) R y R R R x y x u f R S 5 A S 1 B S . 1 x u 5 312° B S B S A S 1 y 1 x B S 1 A S . B S 2 A S 1 x 295.0° u 5 tan 2 1 31 2 6.00 cm 2 / 1 2.80 cm 24 5 2 65.0°. R 5 "1 2.80 cm 2 2 1 1 2 6.00 cm 2 2 5 6.62 cm; 2 6.00 cm R y 5 B y 1 1 2 A y 2 5 2 3.75 cm 1 1 2 2.25 cm 2 5 R x 5 B x 1 1 2 A x 2 5 4.10 cm 1 1 2 1.30 cm 2 5 2.80 cm; 1 x 344.5° u 5 tan 2 1 31 2 1.50 cm 2 / 1 5.40 cm 24 5 2 15.5°. R 5 " R x 2 1 R y 2 5 "1 5.40 cm 2 2 1 1 2 1.50 cm 2 2 5 5.60 cm; R y 5 A y 1 B y 5 2.25 cm 1 1 2 3.75 cm 2 5 2 1.50 cm R x 5 A x 1 B x 5 1.30 cm 1 4.10 cm 5 5.40 cm; Models, Measurements, and Vectors 1-13...
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