PHY2053_F01_final - 211 11 Insruct J. .B uchlr ,J.Ip s r t...

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Unformatted text preview: 211 11 Insruct J. .B uchlr ,J.Ip s r t or: R e e PHYSIC S DE PA R T ME N T PHY 2 053 N a m e ( ri ,l trs) p nt as t: Fi lE xa m na Si t e : gna ur O n m y hono r,I have ne ihe r gi n nor rece i t ve vedunaut iedai hor z don t se xam i i hi naton. YO UR T E ST N UM B E R IS T HE 5DIGIT N UM B E R A T T HE T O P O F E A C H PA GE . 211 11 De ce m be r 8,2 001 DIR E C T IO N S ( ) C o d yo ur t s 1 e e tnum be r o n yo ur a ns e r s e t( e 7 6 { f r t 5- i tnum be r ) o d your na m e on your w he us 80 o he d gi .C e a ns e r s e t w he .Dar ke n ciclsco m p lt l o d your sudntnum be r on your ans e r s e t r e e e y.C e t e w he . ( ) Pr i 2 ntyour nam e on t ss e ta ndsgn i lo. hi he i ta s ( Do a l cra t w ork a nyw he re on t se xa m t 3) ls ch hi hatyou l .A tt e ndoft t s,t se xam p ri outi o be t i ke he he e t hi nt st urne di n. N o cre d i i l gi n w ihoutbot a ns e r s e ta ndp ri outw ih s t w ork m os ue si tw lbe ve t h w he nt t cra ch tq tonsdm a nd e . () B l 4 acke n t cicl o f yo ur i e ndda ns e r co m p lt l he r e nt e w e e y,usng a num be r 2 p e nci Do notm a ke any sray i l . t m ar ksor t a ns e r s e tm ay notre a dp rop e rl he w he y. ( T he a ns e rsa re rounddo.C ho os t cl e s o e xa ct he re i 5) w e e he os tt .T sno p e na ly f gue si t or sng. >>>>>>>>W HE N YO U FIN ISH < < < < < < < < Ha ndi t a ns e r s e ts p a ra t l n he w he e e y. g= 9 : m / 2 8 s 1m i= 1 1 m 6 0 G = 6 : 7 1 1 N m 2 / 2 w a t r = 1 3 kg/ 6 0 1 kg 0 m e 1 2 Mom e ntofi r ta : s i ne i ol dcyl e r : I = 2 M R i nd 2 s i p he re : I = 5M R2 ol ds 1 .A s i ba l sa rtng f ol d l t i rom re s, l ow n t hi i t daw , t rol sd he l n he r l i ng.A tt e ndof t hi he ba l com e sai ne ,lavi he he l lt lbe rbor e ng a tan a ngl of35w ih re s e ctt t gr ound t rm i t e t p o he .De e ne he ra nge x . ( )2 .2 1 4 ( )3. 2 38 ( . 3)484 ( )16 9 4 . ( .0 5)2 9 3 2 .A bow l bal ncount rsa 0.6 0- ve rtca lrie on t w ay i ng le e 7 m i s he ba ck t t ba l ck,a si usra t d Ignore f ctona ll s s o he lra l t e . l ri i ose a nda sum e rol ng w ihoutsi p i a ndt s l i t l ng p hatt m a s he sof t he ba l sd t but duni li i ri e s f l orm y.If t t nsatona ls e e doft he ra l i p he ba l s40 m / tt botom oft rie ,ndt ta nsa tonal li . sa he t he s he r li s e e da tt t . p he op ( )2 . 1 32 ( )105 2 . ( 3)5. 56 ( )5.6 4 1 ( . 5)2 51 211 11 3.B y m e a nsof a r op e w hos m a s sne gl bl,t o bl cksar e s e si i e w gi o us p e nddove r a p ul y,ass n. T he p ul y ca n be t a t dasa e l e how l e re e uni f orm s i ol dcyl ri ld k. T he d nw a rda cce lr aton of t i ca i nd s ow e i he 4 . kg bl ck d t t f 40o ue o he orce ofgraviy,i t sobs r ve dt be e xa cty e o l g=2 . N otng t tt t nson i t rop e i i ha he e i n he snott s m e on e a ch he a sd oft p ul y,ndt m as ie he l e he soft p ul y,i kg. he l n e 211 11 ( )2 2 1 ( )30 2 ( 0 3)1 ( )5 4 ( 5 5)2 4 he oi n a hyd ul ca r l tha sa dnst of 8: 1 2 kg/ 3 . .T li ra i c i f e iy 00 0 m T he w e i ghtoft lf -i e p it i gl bl.T he ra di he lf he e tsd son sne i e gi ioft e t sd p it andr i -i e p it a re 8: 1 3 m a nd0.4 m , i e son ghtsd son 00 0 10 re s e ctve l p i y.W ha ti utf np orce F (n N )i e ddt s p or tt i sne e o up he 2 2 300- com bi dw e i N ne ghtofa ca r a ndt out utp it w he n t he p son, he botom s a ce soft p it t urf he sonsar e a tt lve l how n. he e ss ( )7 47 1 . ( )7 0. 2 1 ( 3)80. 2 ( )7 2 . 4 8 ( 6. 5)7 2 5.A s ri i ta che dt t botom ofa n e m p t s i m i p o ol w ih t a xi p ng sa t o he t y w m ng , t he soft s ri orint dve rtca l he p ng e e i l y.A hol l ow 8. kg bl ck of w o o d( e nst of w o o d= 84 kg/ 3 )i 00o d iy 0 m sxe dt t t of t s ri a ndcom p re se si. T he n t o he op he p ng s t he p o oli ldw ih w at r,com p lt l cove ri t blck.T he s ri i sl e t e e e y ng he o p ng snow obs rve dt be sre t dt i a sm uch a si e o t che w ce t ha dbe e n com p r e se d t rm i t p e rce nt oft bl ck' ot lvol e t ti s .De e ne he age he o st a um ha shol .Ignor e a ny a i i t hol l ow r n he l ow s a ce . p ( )6 0. 1 3% ( )50.% 2 2 ( 5.% 3)7 1 ( )4 3% 4 8. ( 5)58.% 2 6 .A p l oundca rous li re e t r ot t a boutisce nt r on f i i e s a ri .T he ca rous lhasa n a ngulr s e e dof aygr e sf o a e t e r ctonl sbe ngs e a p 3.4ra ds a m om e ntofi rta of1 5 kg 2 , ndra dusof150 m .A 4 0- p e r s sa ndng si xtt t ca rous l 1 /, ne i 2 m a i . 0. kg on, t i tl lne o he e , jum p sont i ry cl e t t out r e d .Fi he re s tng angulr s e e d( ds o tve os o he e ge ndt uli a p ra / )oft car ous landp e rs he e on. ( )183 1 . ( )5.0 2 4 ( .2 3)2 1 ( )2 . 4 38 ( 5)3.4 1 7 .A p e rs w e i ng 500 N sa nd on ghi t son a f e n lke ,hol i a ba g of gol roz a dng dcoi nsof m a s s4kg i t a l n ot .She i s4m aw ay f rom s i ol dground he co e cintof f i i on t i i = 0: .T e r cton he ce s 005.She t ok PhyscsI andre alz st o i ie hatby t hrow i ng s e oft gol om he daw ay,s ca n re a ch s i he ol dground sum i t .A s ng hats ca n t ow t gol he hr he dhoriont l w ih a s e e dof z al y t p 1 m / ,w hati he m a xi um % oft ori na lgol hats ca n have lf he w he n re a che st e d ? 0 s st m he gi dt he e ts he ge ( )1 1 9% ( )1 2 00% ( 3)81 % ( )1 4 5% ( 2% 5)2 8.Sa t l t sA a ndB a re i cicul orbisof ra d A a ndRB ,re s e ctve l bouta p lne t he m a s e le i n r ar t i iR p i y,a a .T sofA i w i t t st ce ha ofB . T he f ce on B i tm e st f ce on A . T he s e e dofA i isorbi s1 3 m / .W hati he s e e d i m / ,ofB or s8 i he or p n t ti 0 s st p ,n s i isorbi? n t t ( )2 1 3 1 0 ( )51 2 2 0 ( 3)41 3 0 ( )8 1 3 4 0 ( 5)8 1 2 0 211 11 9 .T w o blcksofm as o sM a re conne ct dt t r by a rop e andm ove e oge he ~ t t r a bove t ground he t bl ck i ct don by a f oge he he .T op o sa e orce F , dre ct d ta n a ngl w ih re s e ctt t ve rtcal i e a e t p o he i and ofm a gniud t e s t tt ve rtca l cce lr aton i e r o.T he bl uch ha he i a e i sz ockshave t s m e he a horiont lacce lra ton.W ha ti he va l oft angl t tt z a e i st ue he e ha he rop e m a ke sw ih t ve rtca l t he i ? 211 11 ( )none oft s 1 he e ( ) 2 2 ( 3)0 ( )=2 4 ( 5)2 1 0.A ut A ofm a s 1 3 kg sri st re a r ofaut B ,ofm as 03 o s2 0 t ke he o s1 kg,w hi i niil a tre s.A ut A i niil m ovi a l t ch si ta l y t o si ta l y ng ong he x- xi. A f e r t col son,B i ovi w ih s e e d1 m / ta n a s t he li i sm ng t p 5 sa a ngl of30w ih r e s e ctt t x a xi, e t p o he s andA i ovi w ih s e e d sm ng t p 2 5 m / .W ha ti he i tals e e dofA ,i m / ? s st nii p n s ( )312 1 . ( )2 46 2 . ( 3. 3)4 2 ( )512 4 . ( 2. 5)6 5 1 .St rtng f 1 a i rom r e s,a cat p ul cce lra t sa i lne A ofm a s t a ta e e rp a sM t na ls e e dV by a p p l ng a consa ntf o p yi t orce F ove r a dsa nce L . A ga i sa rtng f it n t i rom re s,t ca t p ul cce lra t sa i lne B ofm a s t he a ta e e rp a s3M by a p p l ng t ss e consa nt yi hi am t f ce F ,butnow ove r a dsa nce 2 L . To w ha tna ls e e dd e st ca t p ul cce lr at B ? or it p o he a ta e e ( )0. V 1 82 ( )0.1V 2 7 ( 3)0.0 V 6 ( )0. V 4 53 ( 5)0.4V 4 1 .A t i i rave l w ih s e e d2 0 m / ltve t t ground 2 ra n st i ng t p sre a i o he .A chi hrow sa ba l ow a rdt re a r of t t i l dt lt he he ra n,atan a ngl of e 6 0a bove t horiont he z alandw ih s e e d1 m / ,a sm e as don t p 0 s ure , t t i he ra n.How f r d e st bal t l w ih re s e ctt t gr ound a o he l rave , t p o he be f i t ore tre urnst t he i o he ghtf rom w hi i a st ch tw hrow n? ( )2 6 . m 1 6 ( )35. 2 4m ( 42 m 3)4 . ( )312 m 4 . ( 9. m 5)4 6 1 3.A ro ck i hrow n outw ih s e e d1 m / rom a t e r ofhe i st t p 5 sf ow ght2 0 m ,a tan a ngl of 30a bove t horiont .How l i he ro ck e he z al ong st i t a i be f e i a l o a he i n he r or tf l st ghtof1 m a bove t ground 0 he ? ( )2 . 1 4s ( )0. s 2 9 ( .s 3)13 ( )18 s 4 . ( .s 5)2 9 1 .A ba l sd p e d(niils e e d= 0)f 4 li rop i ta p rom a he i ghtof 30 m .O ne s condlt r a not r bal st e a e he li hrow n sra i t ghtup f om r t groundw ih s e e dv0. T he ba l a s a ch ot r a ta p oi 0 m a bove t ground ha ti he va l ofv0 i m / ? he t p l sp se he nt1 he .W st ue n s ( )1 . 1 48 ( )7 . 2 2 ( 16 3)2 . ( )30. 4 0 ( 5)39 . 4 1 5.A n a ut a cce lr at sa ta consa ntra t f o e e t e rom r e s o 30 m / n 1 sa ndt dce lr at sa ta consa ntra t of2 m / 2 untl tt si 0 he e e e t e s i i tcom e st re s ga i o ta n.A sum e one - i e nsona lm oton.W hati he ave r age s e e doft aut i m / or t st p ? s d m i i st p he o n sf hi ri ( )1 1 5 ( )1 2 0 ( 3)5 ( )2 0 4 ( . 5)2 5 211 11 211 11 ...
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This note was uploaded on 04/29/2008 for the course PHY 2053 taught by Professor Buchler during the Spring '06 term at University of Florida.

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