03_InstSolManual_PDF_Part4

03_InstSolManual_PDF_Part4 - 0.385 m y 2 y 5 v y t 1 1 2 a...

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3.6. Set Up: Use coordinates with the origin at the initial position of the stone and take downward. Solve: (a) and (b) The graph of y versus x is shown in Figure 3.6. Figure 3.6 3.7. Set Up: Take to be in the horizontal direction of the initial velocity and take to be downward. Then and Find t for the bullet to travel horizontally the distance to the target and then calculate the vertical displacement for this t . Solve: (a) gives The vertical displacement during this time is (b) Now and 3.8. Set Up: Take downward, so and Solve: (a) This is the height of the tabletop. (b) (c) and The velocity of the book just before it hits the floor has magnitude and is directed at below the horizontal. 3.9. Set Up: Take downward, so and When the ball reaches the floor, Solve: (a) gives (b) gives Since v 0 5 v 0 x 5 3.58 m / s. v 0 y 5 0, v 0 x 5 x 2 x 0 t 5 1.40 m 0.391 s 5 3.58 m / s. x 2 x 0 5 v 0 x t 1 1 2 a x t 2 t 5 Å 2 1 y 2 y 0 2 a y 5 Å 2 1 0.750 m 2 9.80 m / s 2 5 0.391 s. y 2 y 0 5 v 0 y t 1 1 2 a y t 2 y 2 y 0 5 0.750 m. v 0 y 5 0. a y 51 9.80 m / s 2 a x 5 0, 1 y 72.2° 3.60 m / s u5 72.2°. tan u5 0 v y 0 0 v x 0 5 3.43 m / s 1.10 m / s v 5 " v x 2 1 v y 2 5 3.60 m / s. v y 5 v 0 y 1 a y t 5 1 9.80 m / s 2 21 0.350 s 2 5 3.43 m / s. v x 5 v 0 x 5 1.10 m / s, x 2 x 0 5 v 0 x t 1 1 2 a x t 2 5 1 1.10 m / s 21 0.350 s 2 5
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Unformatted text preview: 0.385 m y 2 y 5 v y t 1 1 2 a y t 2 5 1 2 1 9.80 m / s 2 21 0.350 s 2 2 5 0.600 m. v y 5 0. v x 5 1.10 m / s a y 5 1 9.80 m / s 2 , a x 5 0, 1 y y 5 1 2 1 32 ft / s 2 21 0.600 s 2 2 5 5.8 ft t 5 0.600 s. x 5 450.0 ft y 2 y 5 v y t 1 1 2 a y t 2 5 1 2 1 32 ft / s 2 21 0.200 s 2 2 5 0.64 ft. t 5 x 2 x v x 5 150.0 ft 750 ft / s 5 0.200 s. x 2 x 5 v x t 1 1 2 a x t 2 v y 5 0. v x 5 750 ft / s a y 5 32 ft / s 2 , a x 5 0, 1 y 1 x g 5 32 ft / s 2 . 100 100 200 300 400 500 200 300 400 x 1 m 2 y 1 m 2 O y 5 490 m x 5 300 m, t 5 10 s: y 5 314 m; x 5 240 m, t 5 8 s: y 5 176 m; x 5 180 m, t 5 6 s: y 5 78.4 m; x 5 120 m, t 5 4 s: y 5 19.6 m; x 5 60 m, t 5 2 s: y 5 1 2 gt 2 5 1 4.9 m / s 2 2 t 2 . x 5 v x t 5 1 30 m / s 2 t x 5 y 5 0. a y 5 g 5 9.8 m / s 2 a x 5 0, v y 5 0, 30 m / s, v x 5 1 y 3-4 Chapter 3...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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