03_InstSolManual_PDF_Part9

03_InstSolManual_PDF_Part9 - 5 17.7 m s v y 5 v y 1 a y t 5...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
(b) Use the horizontal motion to find the time in the air. The grasshopper travels horizontally gives Find the vertical displacement of the grasshopper at The height of the cliff is 4.66 m. 3.23. Set Up: Let be upward. Solve: (a) gives and (b) At the highest point and At all points in the motion, downward. (c) Find when and Reflect: The acceleration is the same at all points of the motion. It takes the water to reach its maximum height. When the water reaches the building it has passed its maximum height and its vertical component of velocity is downward. 3.24. Set Up: Example 3.5 derives Solve: The maximum range occurs when and 3.25. Set Up: Example 3.5 gives and Solve: (a) R is a maximum when (b) (c) 3.26. Set Up: Example 3.5 derives Solve: is proportional to so when is tripled, is increased by a factor of 9. 13.5 km. R max 5 9 1 1500 m 2 5 1.35 3 10 4 m 5 R max v 0 v 0 2 R max R max 5 v 0 2 g . R 5 v 0 2 sin 2 u 0 g . h 5 v 0 2 sin 2 45° 2 g 5 v 0 2 4 g 5 R max 4 5 5.75 m R max 5 v 0 2 g 5 1 15.0 m / s 2 2 9.80 m / s 2 5 23.0 m u 0 5 45°. h 5 v 0 2 sin 2 u 0 2 g . R 5 v 0 2 sin 2 u 0 g u 0 5 45°. 2 u 0 5 90° sin 2 u 0 5 1, R 5 v 0 2 sin 2 u 0 g . 2.04 s t 5 2 v 0 y a y 5 2 20.0 m / s 2 9.80 m / s 2 5 v 5 " v x 2 1 v y 2 5 " 1 15.0 m / s 2 2 1 1 2 9.41 m / s 2 2 5 17.7 m
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 5 17.7 m / s v y 5 v y 1 a y t 5 1 25.0 m / s 21 sin 53.1° 2 2 1 9.80 m / s 2 21 3.00 s 2 5 2 9.41 m / s, v x 5 v x 5 15.0 m / s, y 2 y 5 v y t 1 1 2 a y t 2 5 1 25.0 m / s 21 sin 53.1° 21 3.00 s 2 1 1 2 1 2 9.80 m / s 2 21 3.00 s 2 2 5 15.9 m t 5 3.00 s: y 2 y a 5 9.80 m / s 2 v 5 " v x 2 1 v y 2 5 15.0 m / s. v y 5 v x 5 v x 5 1 25.0 m / s 2 cos 53.1° 5 15.0 m / s, u 5 53.1° cos u 5 45.0 m 1 25.0 m / s 21 3.00 s 2 5 0.600; x 2 x 5 v 1 cos u 2 t x 2 x 5 v x t 1 1 2 a x t 2 v y 5 v sin u . v x 5 v cos u , a y 5 2 9.80 m / s 2 . a x 5 0, 1 y y 2 y 5 v y t 1 1 2 a y t 2 5 1 1.15 m / s 21 1.10 s 2 1 1 2 1 2 9.80 m / s 2 21 1.10 s 2 2 5 2 4.66 m t 5 1.10 s: t 5 x 2 x v x 5 x 2 x v cos 50.0° 5 1.10 s x 2 x 5 v x t 1 1 2 a x t 2 x 2 x 5 1.06 m. Motion in a Plane 3-9...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern