03_InstSolManual_PDF_Part16

03_InstSolManual_PDF_Part16 - y 5 8.00 m u 5 60.0°. y 5 1...

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3.54. Set Up: The boat travels due north so is north. east. Solve: (a) The relative velocity addition diagram is shown in Figure 3.54a. and The boat should head west of north. Figure 3.54 (b) (c) To cross the river in the shortest time, needs to have the largest possible northward component. This occurs for north; the boat should head straight across the river. The relative velocity addition diagram is given in Fig- ure 3.54b. and and The boat lands 6.7 m downstream. 3.55. Set Up: Let be upward. With x and y are related by when Solve: (a) (b) gives and below the horizontal. Reflect: We can check our calculated Then which checks. 1 14.4 m / s 21 2.17 s 2 2 1 4.9 m / s 2 21 2.17 s 2 2 5 8 m, y 2 y 0 5 v 0 y t 1 1 2 a y t 2 5 t 5 x 2 x 0 v 0 x 5 18.0 m 8.3 m / s 5 2.17 s. v 0 . u5 40.5°, tan u5 0 v y 0 0 v x 0 5 7.1 8.3 v 5 " v x 2 1 v y 2 5 10.9 m / s. v y 52 "1 v 0 sin u 0 2 2 1 2 a y 1 y 2 y 0 2 52 "1 14.4 m / s 2 2 1 2 1 2 9.80 m / s 2 21 8.00 m 2 52 7.1 m / s v y 2 5 v 0 y 2 1 2 a y 1 y 2 y 0 2 v x 5 v 0 x 5 v 0 cos u 0 5 8.3 m / s. v 0 5 Å gx 2 2 1 cos 2 u 0 21 x tan u 0 2 y 2 5 16.6 m / s x 5 18.0 m.
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Unformatted text preview: y 5 8.00 m u 5 60.0°. y 5 1 tan u 2 x 2 g 2 v 2 cos 2 u x 2 . x 5 y 5 0, a y 5 2 9.80 m / s 2 . a x 5 0, 1 y d 5 1 v B / E 2 east t 5 1 1.0 m / s 21 6.67 s 2 5 6.7 m. 1 v B / E 2 east 5 v W / E 5 1.0 m / s t 5 d 1 v B / E 2 north 5 20 m 3.0 m / s 5 6.67 s 1 v B / E 2 north 5 v B / W 5 3.0 m / s v S B / W v S B / E t 5 d v B / E 5 20 m 2.8 m / s 5 7.1 s v B / E 5 v B / W cos f 5 1 3.0 m / s 2 cos 20° 5 2.8 m / s. v B/E v W/E v B/W N S E W ( b ) v B/E v W/E v B/W N S E W ( a ) f 20° f 5 20°. sin f 5 v W / E v B / W 5 1.0 m / s 3.0 m / s v S B / E 5 v S B / W 1 v S W / E v B / W 5 3.00 m / s. v S W / E 5 1.00 m / s, v S B / E 3-16 Chapter 3...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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