04_InstSolManual_PDF_Part1

04_InstSolManual_PDF_Part1 - NEWTON’S LAWS OF MOTION 4 8....

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Unformatted text preview: NEWTON’S LAWS OF MOTION 4 8. D 9. A 10. C 11. A, D 12. A 13. B 14. E 15. B 16. C Answers to Multiple-Choice Problems 1. C 2. B 3. B 4. A 5. D 6. C 7. B Solutions to Problems 4.1. Set Up and Solve: The horizontal component of the force is 1 10 N 2 cos 45° 5 7.1 N, to the right, and the vertical component is 1 10 N 2 sin 45° 5 7.1 N, downward. Rx 5 g Fx and Ry 5 g Fy. 4.2. Set Up: Take 1x to be along the direction of the pull of A. The coordinates and forces are shown in Figure 4.2. y FB x 60.0° FA Figure 4.2 Solve: FAx 5 FA 5 270 N. FAy 5 0. FBx 5 FB cos 60.0° 5 150 N. FBy 5 FB sin 60.0° 5 260 N. Rx 5 FAx 1 FBx5 270 N 1 150 N 5 420 N. Ry 5 FAy 1 FBy 5 260 N. R 5 "Rx2 1 Ry2 5 494 N. tan u 5 S Ry Rx 5 260 N . 420 N R makes an angle of 31.8° with the rope of dog A. 4 -1 ...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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