04_InstSolManual_PDF_Part17

04_InstSolManual_PDF_Part17 - 3 N, mg 2 F 5 2 ma . g F y 5...

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4.55. Set Up: Use coordinates with upward. The free-body diagram for the astronaut is given in Figure 4.55. The force T is what the scale reads. The rocket and the astronaut have the same acceleration. Figure 4.55 Solve: (a) gives so (b) (i ) On earth: (ii ) On the Moon: 4.56. Set Up: Take downward. While he is in the air, before he touches the ground, his acceleration is Solve: (a) and gives (b) gives The acceleration is upward. (c) The free-body diagram is given in Figure 4.56. is the force the ground exerts on him. Figure 4.56 (d) gives upward. so (e) The reaction force is the man pushing downward on the ground with a force of 4.53 3 10 3 N. F 5 6.16 w . F w 5 4.53 3 10 3 N 1 75.0 kg 21 9.80 m / s 2 2 5 6.16, F 5 m 1 g 1 a 2 5 1 75.0 kg 21 9.80 m / s 2 1 50.6 m / s 2 2 5 4.53 3 10
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Unformatted text preview: 3 N, mg 2 F 5 2 ma . g F y 5 ma y F x y mg v a F S a y 5 v y 2 2 v y 2 2 1 y 2 y 2 5 2 1 7.79 m / s 2 2 2 1 0.60 m 2 5 2 50.6 m / s 2 . v y 5 7.79 m / s, v y 5 0, y 2 y 5 0.60 m. v y 2 5 v y 2 1 2 a y 1 y 2 y 2 v y 5 " 2 a y 1 y 2 y 2 5 " 2 1 9.80 m / s 2 21 3.10 m 2 5 7.79 m / s v y 2 5 v y 2 1 2 a y 1 y 2 y 2 a y 5 9.80 m / s 2 . y 2 y 5 3.10 m, v y 5 0, 9.80 m / s 2 . a y 5 1 y 1 64.4 kg 21 1.67 m / s 2 2 5 108 N w M 5 mg M 5 w E 5 mg E 5 1 64.4 kg 21 9.80 m / s 2 2 5 631 N. m 5 T g 1 a 5 188 N 1.67 m / s 2 1 1.25 m / s 2 5 64.4 kg T 2 mg 5 ma g F y 5 ma y x y T mg 1 y Newton’s Laws of Motion 4-17...
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This note was uploaded on 03/06/2009 for the course PHYS 114 taught by Professor Shoberg during the Spring '07 term at Pittsburg State Uiversity.

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