04_InstSolManual_PDF_Part18

04_InstSolManual_PDF_Part18 - 1 a x t a x 5 v x 2 2 v x 2 2...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
4.57. Set Up: Let be upward. is the force of air resistance. Solve: (a) (b) The free-body diagram is given in Figure 4.57. The net force is upward. Figure 4.57 (c) upward. Reflect: Both the net force and the acceleration are upward. Since her velocity is downward and her acceleration is upward, her speed decreases. 4.58. Set Up: Let be in the direction of motion of the electron. Solve: (a) gives (b) gives (c) g F x 5 ma x 5 1 9.11 3 10 2 31 kg 21 2.50 3 10 14 m / s 2 2 5 2.28 3 10 2 16 N. t 5 v x 2 v 0 x a x 5 3.00 3 10 6 m / s 2 0 2.50 3 10 14 m / s 2 5 1.2 3 10 2 8 s v x 5 v 0 x
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 a x t a x 5 v x 2 2 v x 2 2 1 x 2 x 2 5 1 3.00 3 10 6 m / s 2 2 2 2 1 1.80 3 10 2 2 m 2 5 2.50 3 10 14 m / s 2 v x 2 5 v x 2 1 2 a x 1 x 2 x 2 v x 5 3.00 3 10 6 m / s. 1 x 2 x 2 5 1.80 3 10 2 2 m, v x 5 0, 1 x a y 5 g F y m 5 81 N 55.0 kg 5 1.5 m / s 2 , F air v a y x w g F y 5 F air 2 w 5 620 N 2 539 N 5 81 N. w 5 mg 5 1 55.0 kg 21 9.80 m / s 2 2 5 539 N F S air 1 y 4-18 Chapter 4...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online